category stringclasses 19
values | ctf_task_type stringclasses 7
values | dataset stringclasses 1
value | id stringlengths 29 29 | messages listlengths 3 3 | metadata unknown | source_dataset stringclasses 3
values | source_path stringlengths 0 93 | split stringclasses 1
value | type stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|
kernel | pwn | ctf-dataset | ctf-lora-122e78d21f9c4a461120 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Kernel/CVE-2026-53362_lts/exploit/lts-6.12.85/libxdk-v0.1/xdk/util/str.h` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-0bafb1bcd595ebd6",
"original_line": 316,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/CVE-2026-53362_lts/exploit/lts-6.12.85/lib... | pwn101_distilled_v1 | Kernel/CVE-2026-53362_lts/exploit/lts-6.12.85/libxdk-v0.1/xdk/util/str.h | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-130190b9a72792a82213 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「exp」。\n资料来源：Heap/tcache attack/tcache key/readme.md；主题：2.33堆申请规则；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或命令。",
... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-d31c7c9b716b0585",
"original_line": 148,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/tcache attack/tcache key/readme.md",
"split": "tra... | pwn101_distilled_v1 | Heap/tcache attack/tcache key/readme.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-136bc60e10deae6913ff | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「前言」。\n资料来源：Kernel/2022ciscn-cactus/wp.md；主题：CISCN 2022 西南赛区半决赛 cactus WP；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块... | {
"category": "kernel",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-1be48617c12d1bbd",
"original_line": 335,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2022ciscn-cactus/wp.md",
"split": "train",
"... | pwn101_distilled_v1 | Kernel/2022ciscn-cactus/wp.md | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-138b1614d39739802dd9 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Stack/ret2syscall/x64/[MoeCTF 2022]syscall/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"rol... | {
"category": "stack",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-83ff2f9f76445a7a",
"original_line": 556,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Stack/ret2syscall/x64/[MoeCTF 2022]syscall/exp.py"... | pwn101_distilled_v1 | Stack/ret2syscall/x64/[MoeCTF 2022]syscall/exp.py | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-13d267a60e72341d2f6b | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Kernel/QWB2021-notebook/exp.c` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
{
... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-21789f1e8c88f096",
"original_line": 323,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/QWB2021-notebook/exp.c",
"split": "train... | pwn101_distilled_v1 | Kernel/QWB2021-notebook/exp.c | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-13dba371fc77f3d99c00 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「1. 布局堆块」。\n资料来源：IO-FILE/house of storm/2026ccb catchme/wp.md；主题：2026ccb catchme；分类：io_file。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保... | {
"category": "io_file",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-f79f2a52b848226c",
"original_line": 239,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/house of storm/2026ccb catchme/wp.md",
"spli... | pwn101_distilled_v1 | IO-FILE/house of storm/2026ccb catchme/wp.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-147c4b43c901fdcf9431 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「ioctl 伪代码」。\n资料来源：Kernel/2026d3ctf-d3kheap2pro/README.md；主题：2026d3ctf-d3kheap2pro；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-b87f3888856e509e",
"original_line": 366,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2026d3ctf-d3kheap2pro/README.md",
"split": "tr... | pwn101_distilled_v1 | Kernel/2026d3ctf-d3kheap2pro/README.md | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-14fe276346460e3b1f6c | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「3.2 largebin attack 写 `_IO_list_all`」。\n资料来源：IO-FILE/house of apple2/2024ylb futureheap/WP.md；主题：2024ylb futureheap WP；分类：io... | {
"category": "io_file",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-50e0fbd2c2ecc405",
"original_line": 203,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/house of apple2/2024ylb futureheap/WP.md",
"... | pwn101_distilled_v1 | IO-FILE/house of apple2/2024ylb futureheap/WP.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-1552776ed65df4c4ca14 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "根据 `Kernel/2026d3ctf-d3kheap2pro` 目录下的 writeup 和 exploit 示例，蒸馏一条训练样本：总结题目、漏洞点、利用链、关键代码和验证状态。",
"role": "user"
},
{
"content": "## 题目路... | {
"category": "kernel",
"ctf_score": 40,
"ctf_task_type": "pwn",
"original_id": "pwn101-pair-4a0cde6d49b0fe3c",
"original_line": 413,
"original_split": "train",
"record_type": "writeup_exploit_pair",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2026d3ctf-d3kheap2pro",
"split": "tr... | pwn101_distilled_v1 | Kernel/2026d3ctf-d3kheap2pro | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-163dea7f21f7c9ec02ad | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「3. tcache poisoning 绕过 Safe-Linking」。\n资料来源：IO-FILE/[CISCN 2022 华东北]duck/WP.md；主题：[CISCN 2022 华东北] duck - Pwn Writeup；分类：io_... | {
"category": "io_file",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-57c367bf7340d5fe",
"original_line": 182,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/[CISCN 2022 华东北]duck/WP.md",
"split": "train... | pwn101_distilled_v1 | IO-FILE/[CISCN 2022 华东北]duck/WP.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-16fc8202f2fbde0772dd | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「PTE spray and stale second-free tests」。\n资料来源：Kernel/2026d3ctf-d3kheap2pro/XCACHE_RESULTS.md；主题：d3kheap2pro cross-cache / Di... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-e44c21286488176d",
"original_line": 386,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2026d3ctf-d3kheap2pro/XCACHE_RESULTS.md",
"spl... | pwn101_distilled_v1 | Kernel/2026d3ctf-d3kheap2pro/XCACHE_RESULTS.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-17e14cce4b5e5d21f9d0 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「Exploit Summary」。\n资料来源：Kernel/CVE-2026-53362_lts/docs/exploit.md；主题：Exploit；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中... | {
"category": "kernel",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-0df5abeed808dfe2",
"original_line": 387,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/CVE-2026-53362_lts/docs/exploit.md",
"split": ... | pwn101_distilled_v1 | Kernel/CVE-2026-53362_lts/docs/exploit.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-18bcdce4edbbd6985bdb | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「core_pattern flag path」。\n资料来源：Kernel/CVE-2026-53362_lts/docs/exploit.md；主题：Exploit；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点... | {
"category": "kernel",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-9d94bcedccbfe16b",
"original_line": 394,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/CVE-2026-53362_lts/docs/exploit.md",
"split": ... | pwn101_distilled_v1 | Kernel/CVE-2026-53362_lts/docs/exploit.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-1901f73a21c67917c216 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/tcache attack/fastbin_reverse_into_tcache/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-19a00c7d3cf16114",
"original_line": 25,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/tcache attack/fastbin_reverse_into_tcache/exp.p... | pwn101_distilled_v1 | Heap/tcache attack/fastbin_reverse_into_tcache/exp.py | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-194b999506e71acc0dfc | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「Unsortedbin Attack」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-fea405073173ec0b",
"original_line": 111,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_group... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-1a2ba4173b04f4a24ae4 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「初始化和打开」。\n资料来源：Kernel/QWB2018-core/tty_struct.md；主题：tty_struct；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或命令。",
... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-9ee12f38191cbc04",
"original_line": 402,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/QWB2018-core/tty_struct.md",
"split": "train",... | pwn101_distilled_v1 | Kernel/QWB2018-core/tty_struct.md | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-1a7dffedd7e04f34d332 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `IO-FILE/house of apple2/2024pcb babyheap/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role"... | {
"category": "io_file",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-0b5230ee0787d2d8",
"original_line": 155,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/house of apple2/2024pcb babyheap/exp.py"... | pwn101_distilled_v1 | IO-FILE/house of apple2/2024pcb babyheap/exp.py | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-1b525e4e074b19415713 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/2024qwb-baby_heap/exp_cli.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-f7b52bedbcd6b5b6",
"original_line": 1,
"original_split": "validation",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/2024qwb-baby_heap/exp_cli.py",
"split": "... | pwn101_distilled_v1 | Heap/2024qwb-baby_heap/exp_cli.py | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-1c44501f672b88bf9ddd | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「基本概念」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-18c34a18e199f9d1",
"original_line": 59,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_group_... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-1cdafc8a008fe19dab30 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「程序逻辑」。\n资料来源：Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md；主题：CISCN2024 华南赛区 my_heap Writeup；分类：heap。\n要求：结构化说明概念、利用条件、关键结构... | {
"category": "heap",
"ctf_score": 34,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-0827afbc9bf237e2",
"original_line": 128,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md",
"split... | pwn101_distilled_v1 | Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-1e03b08783787ce9b44f | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「栈溢出漏洞」。\n资料来源：stack.md；主题：栈利用；分类：stack。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或命令。",
"role": "user"
},
{
"cont... | {
"category": "stack",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-3ffec1906210efd1",
"original_line": 595,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "stack.md",
"split": "train",
"split_group_key": "5d2... | pwn101_distilled_v1 | stack.md | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-1e2137b3b5cbb9a42427 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Stack/ret2syscall/x86/basic/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},... | {
"category": "stack",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-35413f21a4f37f90",
"original_line": 55,
"original_split": "validation",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Stack/ret2syscall/x86/basic/exp.py",
"split"... | pwn101_distilled_v1 | Stack/ret2syscall/x86/basic/exp.py | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-1eb38b5c397874c944e6 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「分配过程」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-94e4674fd9333c1d",
"original_line": 94,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_group_... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-1ee0587a710c510ec9c8 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「3.4 House of Apple2」。\n资料来源：IO-FILE/house of apple2/2024ylb futureheap/WP.md；主题：2024ylb futureheap WP；分类：io_file。\n要求：结构化说明概... | {
"category": "io_file",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-54196e321d816977",
"original_line": 204,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/house of apple2/2024ylb futureheap/WP.md",
"... | pwn101_distilled_v1 | IO-FILE/house of apple2/2024ylb futureheap/WP.md | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-1f7e2909e339206eccff | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「原理」。\n资料来源：stack.md；主题：栈利用；分类：stack。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或命令。",
"role": "user"
},
{
"content... | {
"category": "stack",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-2a21213af0b1d8c4",
"original_line": 591,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "stack.md",
"split": "train",
"split_group_key": "5d2... | pwn101_distilled_v1 | stack.md | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-202ccf84c64fe109d41f | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「本地验证」。\n资料来源：IO-FILE/[CISCN 2022 华东北]duck/WP.md；主题：[CISCN 2022 华东北] duck - Pwn Writeup；分类：io_file。\n要求：结构化说明概念、利用条件、关键结构/函数、... | {
"category": "io_file",
"ctf_score": 34,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-94fce924c16d40f7",
"original_line": 184,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/[CISCN 2022 华东北]duck/WP.md",
"split": "train... | pwn101_distilled_v1 | IO-FILE/[CISCN 2022 华东北]duck/WP.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-20a16ceb22613a3c6e76 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「Confirmed module primitive」。\n资料来源：Kernel/2026d3ctf-d3kheap2pro/EXP.md；主题：d3kheap2pro exploit notes；分类：kernel。\n要求：结构化说明概念、利... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-8dc8011dd985ec26",
"original_line": 361,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2026d3ctf-d3kheap2pro/EXP.md",
"split": "train... | pwn101_distilled_v1 | Kernel/2026d3ctf-d3kheap2pro/EXP.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-21d39e5e20368c4a9712 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「例题 hitcontraining_magicheap」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用... | {
"category": "heap",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-e68394c1e97e7a55",
"original_line": 105,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_group... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-249aa175dd76990a6401 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Kernel/2024wdb/vir1/vir1_start.sh` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-ce0f4133dcee0dad",
"original_line": 284,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2024wdb/vir1/vir1_start.sh",
"split": "t... | pwn101_distilled_v1 | Kernel/2024wdb/vir1/vir1_start.sh | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-24aed207f34196e48a7f | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「Next experiments」。\n资料来源：Kernel/2026d3ctf-d3kheap2pro/XCACHE_RESULTS.md；主题：d3kheap2pro cross-cache / Dirty Pagetable experim... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-10c4badb5a92fc69",
"original_line": 379,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2026d3ctf-d3kheap2pro/XCACHE_RESULTS.md",
"spl... | pwn101_distilled_v1 | Kernel/2026d3ctf-d3kheap2pro/XCACHE_RESULTS.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-24b615f41af5798f59b7 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Kernel/2022ciscn-cactus/start.sh` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-82f7df6d45e87953",
"original_line": 281,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2022ciscn-cactus/start.sh",
"split": "tr... | pwn101_distilled_v1 | Kernel/2022ciscn-cactus/start.sh | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-250c79dbb0292f50d682 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「注记」。\n资料来源：Kernel/QWB2018-core/tty_struct.md；主题：tty_struct；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或命令。",
"ro... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-6502af70fae858f8",
"original_line": 401,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/QWB2018-core/tty_struct.md",
"split": "train",... | pwn101_distilled_v1 | Kernel/QWB2018-core/tty_struct.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-253b84e514a65936e1d4 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「ioctl 命令」。\n资料来源：Kernel/2026d3ctf-d3kheap2pro/README.md；主题：2026d3ctf-d3kheap2pro；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-607f06792ea33efe",
"original_line": 365,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2026d3ctf-d3kheap2pro/README.md",
"split": "tr... | pwn101_distilled_v1 | Kernel/2026d3ctf-d3kheap2pro/README.md | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-262c345148ad32a692a8 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Stack/ret2shellcode/shellcode_limit/32.c` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user... | {
"category": "stack",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-9562c38b7ef00f5f",
"original_line": 551,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Stack/ret2shellcode/shellcode_limit/32.c",
"spli... | pwn101_distilled_v1 | Stack/ret2shellcode/shellcode_limit/32.c | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-268bd48872b59221b7b2 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/unlink/ZCTF_2016_note3/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-809072282e8b68b6",
"original_line": 42,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/unlink/ZCTF_2016_note3/exp.py",
"split": "tra... | pwn101_distilled_v1 | Heap/unlink/ZCTF_2016_note3/exp.py | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-26f11171b8de5cbcb6fe | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「例题」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-469078237fc29ec4",
"original_line": 70,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_group_... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-2750c690da5d7d7e9d11 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Kernel/RWCTF2022 高校赛 - Digging into kernel/dbg.sh` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"rol... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-b862c270c66026fb",
"original_line": 326,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/RWCTF2022 高校赛 - Digging into kernel/dbg.sh... | pwn101_distilled_v1 | Kernel/RWCTF2022 高校赛 - Digging into kernel/dbg.sh | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-275f52447cada9b75f7f | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「asm(shellcraft.sh())长度为0x30」。\n资料来源：stack.md；主题：栈利用；分类：stack。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或命令。",
"role": "us... | {
"category": "stack",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-dd89e3be3fa762cf",
"original_line": 614,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "stack.md",
"split": "train",
"split_group_key": "5d2... | pwn101_distilled_v1 | stack.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-28016616be0dff670a90 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「申请结构体、链表链接与数据拷贝」。\n资料来源：Kernel/2022ciscn-cactus/wp.md；主题：CISCN 2022 西南赛区半决赛 cactus WP；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构/函数、常见... | {
"category": "kernel",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-3caed60bbe973316",
"original_line": 339,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2022ciscn-cactus/wp.md",
"split": "train",
"... | pwn101_distilled_v1 | Kernel/2022ciscn-cactus/wp.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-280327f56b450ee645ef | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/fastbin attack/fastbin-double_free/roarctf_2019_easyheap/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-e872bf308dca398f",
"original_line": 9,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/fastbin attack/fastbin-double_free/roarctf_2019_... | pwn101_distilled_v1 | Heap/fastbin attack/fastbin-double_free/roarctf_2019_easyheap/exp.py | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-2867870f94e26369330a | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「libc 泄漏」。\n资料来源：IO-FILE/house of apple2/2024pcb babyheap/WP.md；主题：2024PCB babyheap WP；分类：io_file。\n要求：结构化说明概念、利用条件、关键结构/函数、常... | {
"category": "io_file",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-62b896a83ac8be18",
"original_line": 194,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/house of apple2/2024pcb babyheap/WP.md",
"sp... | pwn101_distilled_v1 | IO-FILE/house of apple2/2024pcb babyheap/WP.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-2892c80532ffd6e72c43 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/tcache attack/tcache key/2.33.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-24a506c2df8bc1e4",
"original_line": 35,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/tcache attack/tcache key/2.33.py",
"split": "... | pwn101_distilled_v1 | Heap/tcache attack/tcache key/2.33.py | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-28e9277c0caf3ed6f244 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「PoC」。\n资料来源：Kernel/2022ciscn-cactus/wp.md；主题：CISCN 2022 西南赛区半决赛 cactus WP；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码... | {
"category": "kernel",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-62c1f2badabb6d75",
"original_line": 342,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2022ciscn-cactus/wp.md",
"split": "train",
"... | pwn101_distilled_v1 | Kernel/2022ciscn-cactus/wp.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-2a04dcc1ba13a98f46a5 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/hitcontraining_uaf/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
{... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-ec464ff5e69b88a1",
"original_line": 12,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/hitcontraining_uaf/exp.py",
"split": "train",... | pwn101_distilled_v1 | Heap/hitcontraining_uaf/exp.py | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-2a250ff90d87a0130c1e | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「unlink源码分析」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-c41fb5dde0709533",
"original_line": 6,
"original_split": "validation",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_gr... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-2a66acb7f1d8b8d0725d | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「3.1 堆布局」。\n资料来源：IO-FILE/house of apple2/2024ylb futureheap/WP.md；主题：2024ylb futureheap WP；分类：io_file。\n要求：结构化说明概念、利用条件、关键结构/... | {
"category": "io_file",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-d953c6e5f14e840c",
"original_line": 212,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/house of apple2/2024ylb futureheap/WP.md",
"... | pwn101_distilled_v1 | IO-FILE/house of apple2/2024ylb futureheap/WP.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-2af4f23393faef5b4c8e | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/fastbin attack/house of sprit/2014_hack.lu_oreo/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。"... | {
"category": "heap",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-f3b88377fe47efb2",
"original_line": 11,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/fastbin attack/house of sprit/2014_hack.lu_oreo... | pwn101_distilled_v1 | Heap/fastbin attack/house of sprit/2014_hack.lu_oreo/exp.py | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-2b57df2150e10f308099 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「9. 使用 backdoor 改返回地址并触发返回」。\n资料来源：Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md；主题：CISCN2024 华南赛区 my_heap Writeup；分类：heap。\... | {
"category": "heap",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-c5c0609cb2b6c188",
"original_line": 143,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md",
"split... | pwn101_distilled_v1 | Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-2b64c0c082dfef63eae1 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「msgsnd和msgrcv的源码分析」。\n资料来源：Kernel/readme.md；主题：利用msg_msg实现任意地址读写；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或命令。",
... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-914d8f70c65b82bb",
"original_line": 409,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/readme.md",
"split": "train",
"split_group_k... | pwn101_distilled_v1 | Kernel/readme.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-2c16283d05f5bc2ef098 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Kernel/ciscn2017-babydriver/boot.sh` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
}... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-1c06313fbaf3d8a1",
"original_line": 329,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/ciscn2017-babydriver/boot.sh",
"split": ... | pwn101_distilled_v1 | Kernel/ciscn2017-babydriver/boot.sh | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-2c384f6ec6bb15490947 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Stack/ret2reg/rsp_shellcode/exp_cli.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
... | {
"category": "stack",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-f8f06ddd685d31e2",
"original_line": 544,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Stack/ret2reg/rsp_shellcode/exp_cli.py",
"split"... | pwn101_distilled_v1 | Stack/ret2reg/rsp_shellcode/exp_cli.py | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-2dd428b9fb54238cb415 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Stack/ret2text/ret2text_x86/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},... | {
"category": "stack",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-c94aa40aaa947c09",
"original_line": 562,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Stack/ret2text/ret2text_x86/exp.py",
"split": "t... | pwn101_distilled_v1 | Stack/ret2text/ret2text_x86/exp.py | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-2e1e9abc404eb5d5c616 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「FSOP 构造」。\n资料来源：IO-FILE/2025hgame hit list/WP.md；主题：2025 HGame - Hit list Writeup；分类：io_file。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，... | {
"category": "io_file",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-6d27b1aca05d6511",
"original_line": 167,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/2025hgame hit list/WP.md",
"split": "train",... | pwn101_distilled_v1 | IO-FILE/2025hgame hit list/WP.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-2eee907b14904eb18364 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「2. 泄露 libc base」。\n资料来源：Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md；主题：CISCN2024 华南赛区 my_heap Writeup；分类：heap。\n要求：结构化说明概... | {
"category": "heap",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-67e026e2bae820a1",
"original_line": 137,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md",
"split... | pwn101_distilled_v1 | Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-2f12fce351b81681837e | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「静态分析」。\n资料来源：Heap/tcache attack/2025das rcms/wp.md；主题：2025das rcms；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或命令。",
... | {
"category": "heap",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-d9fad76a72b75ddb",
"original_line": 123,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/tcache attack/2025das rcms/wp.md",
"split": "train... | pwn101_distilled_v1 | Heap/tcache attack/2025das rcms/wp.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-2fa7f4dc0e086f7d6373 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Kernel/xhlj2021-easykernel/exp.c` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-eba42a95145aa3d7",
"original_line": 29,
"original_split": "validation",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/xhlj2021-easykernel/exp.c",
"split":... | pwn101_distilled_v1 | Kernel/xhlj2021-easykernel/exp.c | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-30249f638a1f9e0e6b9b | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `IO-FILE/house of apple2/2025gxqs name/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "... | {
"category": "io_file",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-29919f193bec81e3",
"original_line": 157,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/house of apple2/2025gxqs name/exp.py",
... | pwn101_distilled_v1 | IO-FILE/house of apple2/2025gxqs name/exp.py | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-3040be02ea0f59b61d70 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「清除tcache key」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-1687937dac164960",
"original_line": 58,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_group_... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-30622bf0de0ef06a6bcf | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「MSG_COPY 特例」。\n资料来源：Kernel/2022ciscn-cactus/wp.md；主题：CISCN 2022 西南赛区半决赛 cactus WP；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并... | {
"category": "kernel",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-1bd82cfc70eca879",
"original_line": 334,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2022ciscn-cactus/wp.md",
"split": "train",
"... | pwn101_distilled_v1 | Kernel/2022ciscn-cactus/wp.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-3098856c23e1e0bbe65b | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「示例 2」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-c2b3a7fae7f2ed35",
"original_line": 5,
"original_split": "validation",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_gr... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-30dc49253bd261a7f757 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/off-by-one/2021强网拟态 bitflip/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-b3dd40995db36ad0",
"original_line": 15,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/off-by-one/2021强网拟态 bitflip/exp.py",
"split":... | pwn101_distilled_v1 | Heap/off-by-one/2021强网拟态 bitflip/exp.py | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-30ed3a31b8516f5a70ef | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「4. 触发Storm」。\n资料来源：IO-FILE/house of storm/2026ccb catchme/wp.md；主题：2026ccb catchme；分类：io_file。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点... | {
"category": "io_file",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-1a79faa1677be555",
"original_line": 19,
"original_split": "validation",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/house of storm/2026ccb catchme/wp.md",
"... | pwn101_distilled_v1 | IO-FILE/house of storm/2026ccb catchme/wp.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-3225bd9c601ae238448d | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「Interpretation」。\n资料来源：Kernel/2026d3ctf-d3kheap2pro/XCACHE_RESULTS.md；主题：d3kheap2pro cross-cache / Dirty Pagetable experimen... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-d98aa355fea0ae97",
"original_line": 384,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2026d3ctf-d3kheap2pro/XCACHE_RESULTS.md",
"spl... | pwn101_distilled_v1 | Kernel/2026d3ctf-d3kheap2pro/XCACHE_RESULTS.md | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-32496409abcf7ae8908c | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Stack/ret2dlresolve/2023Newstar-dlresolve/exp_cli.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"... | {
"category": "stack",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-8d67a93474d9597e",
"original_line": 528,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Stack/ret2dlresolve/2023Newstar-dlresolve/exp_cli.... | pwn101_distilled_v1 | Stack/ret2dlresolve/2023Newstar-dlresolve/exp_cli.py | train | ctf_lora_sft |
misc_pwn | pwn | ctf-dataset | ctf-lora-32f5671d5b6f3be99aa8 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `其它/minishell/minishell.c` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
{
"... | {
"category": "misc_pwn",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-f93db350ffff1bb5",
"original_line": 425,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "其它/minishell/minishell.c",
"split": "train",
... | pwn101_distilled_v1 | 其它/minishell/minishell.c | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-3412e6dea1f9b4c3f0c1 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「5. 总结」。\n资料来源：IO-FILE/house of apple2/2024ylb futureheap/WP.md；主题：2024ylb futureheap WP；分类：io_file。\n要求：结构化说明概念、利用条件、关键结构/函数... | {
"category": "io_file",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-3fd26b03f7903f02",
"original_line": 202,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/house of apple2/2024ylb futureheap/WP.md",
"... | pwn101_distilled_v1 | IO-FILE/house of apple2/2024ylb futureheap/WP.md | train | ctf_lora_sft |
misc_vuln | pwn | ctf-dataset | ctf-lora-34178581fdceea9feba0 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `其它漏洞/格式化字符串/hijack retaddr/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
... | {
"category": "misc_vuln",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-af72e7eb4deba065",
"original_line": 460,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "其它漏洞/格式化字符串/hijack retaddr/exp.py",
"split":... | pwn101_distilled_v1 | 其它漏洞/格式化字符串/hijack retaddr/exp.py | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-341ae25364f6efed04ee | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「3. pro 配置阻断公开 d3kheap2 链」。\n资料来源：Kernel/2026d3ctf-d3kheap2pro/ROOT_ANALYSIS.md；主题：d3kheap2pro root 提权可行性分析；分类：kernel。\n要求：结构... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-6e70ad0477efac8b",
"original_line": 370,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2026d3ctf-d3kheap2pro/ROOT_ANALYSIS.md",
"spli... | pwn101_distilled_v1 | Kernel/2026d3ctf-d3kheap2pro/ROOT_ANALYSIS.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-35039e7fc9f320ed633f | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/tcache attack/ciscn2024_华南赛区-myheap/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role"... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-01cc47593ab574e1",
"original_line": 2,
"original_split": "validation",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/tcache attack/ciscn2024_华南赛区-myheap/exp.py"... | pwn101_distilled_v1 | Heap/tcache attack/ciscn2024_华南赛区-myheap/exp.py | train | ctf_lora_sft |
misc_pwn | pwn | ctf-dataset | ctf-lora-364caa9b1937543c1a88 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `其它/2025qwb-ez-stack/e.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
{
"... | {
"category": "misc_pwn",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-ffe480b6d6bd0cea",
"original_line": 421,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "其它/2025qwb-ez-stack/e.py",
"split": "train",
... | pwn101_distilled_v1 | 其它/2025qwb-ez-stack/e.py | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-36c3b8d35525c5819ecb | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「C语言分配函数」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-f4958825aec1b2ac",
"original_line": 109,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_group... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-37193e6b521d3636ae8f | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Stack/花式栈/[HGAME 2023 week1]orw/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
... | {
"category": "stack",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-086b7fd9b997f8a9",
"original_line": 579,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Stack/花式栈/[HGAME 2023 week1]orw/exp.py",
"split"... | pwn101_distilled_v1 | Stack/花式栈/[HGAME 2023 week1]orw/exp.py | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-377df98e0f7d88bdbba4 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「栈上迁移」。\n资料来源：stack.md；主题：栈利用；分类：stack。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或命令。",
"role": "user"
},
{
"conte... | {
"category": "stack",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-ed0651a535c580ea",
"original_line": 619,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "stack.md",
"split": "train",
"split_group_key": "5d2... | pwn101_distilled_v1 | stack.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-3787671843b504117969 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「漏洞点」。\n资料来源：Kernel/2026d3ctf-d3kheap2pro/README.md；主题：2026d3ctf-d3kheap2pro；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的... | {
"category": "kernel",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-87106958d1746a09",
"original_line": 34,
"original_split": "validation",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2026d3ctf-d3kheap2pro/README.md",
"split":... | pwn101_distilled_v1 | Kernel/2026d3ctf-d3kheap2pro/README.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-38f255581b1d09515acd | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「PoC」。\n资料来源：Kernel/2022ciscn-cactus/wp.md；主题：CISCN 2022 西南赛区半决赛 cactus WP；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码... | {
"category": "kernel",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-56cfe0cc1a854abd",
"original_line": 341,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2022ciscn-cactus/wp.md",
"split": "train",
"... | pwn101_distilled_v1 | Kernel/2022ciscn-cactus/wp.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-39f41f8c9bc473483b45 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「UAF 转 heap overlapping」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用条件、关键... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-7d9e03ede92a9e88",
"original_line": 91,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_group_... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-3aa064d1fa16437dd838 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Kernel/0CTF2018-baby/start.sh` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
{
... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-7bf613864cfa352a",
"original_line": 279,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/0CTF2018-baby/start.sh",
"split": "train... | pwn101_distilled_v1 | Kernel/0CTF2018-baby/start.sh | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-3acd3fedb7e2c222aeea | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「本地运行说明」。\n资料来源：Heap/off-by-one/2024ylb-null/WP.md；主题：2024ylb-null Writeup；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或... | {
"category": "heap",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-9ebd7052f8676e85",
"original_line": 118,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/off-by-one/2024ylb-null/WP.md",
"split": "train",
... | pwn101_distilled_v1 | Heap/off-by-one/2024ylb-null/WP.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-3c3b17e7fae9a29a3587 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/off-by-one/2024ylb-null/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
}... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-a92adfc3f5ac8da0",
"original_line": 17,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/off-by-one/2024ylb-null/exp.py",
"split": "tr... | pwn101_distilled_v1 | Heap/off-by-one/2024ylb-null/exp.py | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-3cb7a8a8141a123ae209 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「例题 2021qwnn bitflip」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-4eaef111c34a24ed",
"original_line": 72,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_group_... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-3d3f7e657f5b5e2a604a | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「msgrcv接收数据的调用链及方法」。\n资料来源：Kernel/readme.md；主题：利用msg_msg实现任意地址读写；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或命令。",
... | {
"category": "kernel",
"ctf_score": 34,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-0bc6ec2ef426c9ff",
"original_line": 407,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/readme.md",
"split": "train",
"split_group_k... | pwn101_distilled_v1 | Kernel/readme.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-3d78ba2f51f9744ea26c | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Kernel/2024wdb/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
{
"con... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-bb351c4c27125a7c",
"original_line": 282,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2024wdb/exp.py",
"split": "train",
"sp... | pwn101_distilled_v1 | Kernel/2024wdb/exp.py | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-3d95aa0f6608bb36ef20 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Stack/ret2csu/[NewStarCTF 公开赛赛道]ret2csu1/exp_cli.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"r... | {
"category": "stack",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-c49b89d02d80d8a4",
"original_line": 522,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Stack/ret2csu/[NewStarCTF 公开赛赛道]ret2csu1/exp_cli.p... | pwn101_distilled_v1 | Stack/ret2csu/[NewStarCTF 公开赛赛道]ret2csu1/exp_cli.py | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-3dfb91222ac7e71a04e2 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Kernel/QWB2018-core/exp.c` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
{
... | {
"category": "kernel",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-7384e6c072133aea",
"original_line": 27,
"original_split": "validation",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/QWB2018-core/exp.c",
"split": "train... | pwn101_distilled_v1 | Kernel/QWB2018-core/exp.c | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-3fa61f27bc964ed74a73 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/off-by-one/2021强网拟态 old_school_revenge/oldnull.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
... | {
"category": "heap",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-f1d7cee895961a22",
"original_line": 16,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/off-by-one/2021强网拟态 old_school_revenge/oldnull.... | pwn101_distilled_v1 | Heap/off-by-one/2021强网拟态 old_school_revenge/oldnull.py | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-3ff929b7385340dd0c6d | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「当前结论」。\n资料来源：Kernel/2026d3ctf-d3kheap2pro/README.md；主题：2026d3ctf-d3kheap2pro；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中... | {
"category": "kernel",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-1123b06c95c5c71e",
"original_line": 363,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2026d3ctf-d3kheap2pro/README.md",
"split": "tr... | pwn101_distilled_v1 | Kernel/2026d3ctf-d3kheap2pro/README.md | train | ctf_lora_sft |
seccomp | pwn | ctf-dataset | ctf-lora-40177f943e206906e08e | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Seccomp绕过/2024das sixbytes/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
... | {
"category": "seccomp",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-61f166ec0fbe0a58",
"original_line": 498,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Seccomp绕过/2024das sixbytes/exp.py",
"split": "... | pwn101_distilled_v1 | Seccomp绕过/2024das sixbytes/exp.py | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-405f45dbb5e298780595 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「signal机制」。\n资料来源：stack.md；主题：栈利用；分类：stack。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或命令。",
"role": "user"
},
{
"c... | {
"category": "stack",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-55775aaf75a92544",
"original_line": 598,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "stack.md",
"split": "train",
"split_group_key": "5d2... | pwn101_distilled_v1 | stack.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-40c08e21a6b99bf1ee4c | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/ACTF_2019_babyheap/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
{... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-aaf988383ebeb5ad",
"original_line": 3,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/ACTF_2019_babyheap/exp.py",
"split": "train",
... | pwn101_distilled_v1 | Heap/ACTF_2019_babyheap/exp.py | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-40e8e310d8ca39f10116 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「3.3 伪造 FILE 结构」。\n资料来源：IO-FILE/house of apple2/2024ylb futureheap/WP.md；主题：2024ylb futureheap WP；分类：io_file。\n要求：结构化说明概念、利用条... | {
"category": "io_file",
"ctf_score": 34,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-c39b5b5d3240be41",
"original_line": 210,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/house of apple2/2024ylb futureheap/WP.md",
"... | pwn101_distilled_v1 | IO-FILE/house of apple2/2024ylb futureheap/WP.md | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-40f7582d21ba30c71493 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Stack/ret2shellcode/ez_shellcode/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"... | {
"category": "stack",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-a0797216e245c49f",
"original_line": 546,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Stack/ret2shellcode/ez_shellcode/exp.py",
"split... | pwn101_distilled_v1 | Stack/ret2shellcode/ez_shellcode/exp.py | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-41fb3b98762bef7a87ae | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Kernel/2026d3ctf-d3kheap2pro/make_exp_image.sh` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role":... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-04e0ab2e67da950e",
"original_line": 291,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2026d3ctf-d3kheap2pro/make_exp_image.sh",
... | pwn101_distilled_v1 | Kernel/2026d3ctf-d3kheap2pro/make_exp_image.sh | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-43c4c840324080371047 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「古老的 unlink」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-e6b2bccbf51b7a95",
"original_line": 106,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_group... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-441ca6d5de915cf89a7d | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Kernel/2026d3ctf-d3kheap2pro/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
}... | {
"category": "kernel",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-f96a2125c958c6f7",
"original_line": 289,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2026d3ctf-d3kheap2pro/exp.py",
"split": ... | pwn101_distilled_v1 | Kernel/2026d3ctf-d3kheap2pro/exp.py | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-44796c276c71399ac9d6 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「Leak libc from the reused unsorted-bin chunk.」。\n资料来源：Heap/2024ylb-ezheap/writeup.md；主题：2024ylb-ezheap；分类：heap。\n要求：结构化说明概念、... | {
"category": "heap",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-1d047d795926b108",
"original_line": 47,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/2024ylb-ezheap/writeup.md",
"split": "train",
"sp... | pwn101_distilled_v1 | Heap/2024ylb-ezheap/writeup.md | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-44e5e31f89ed54514dca | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「system call chains」。\n资料来源：stack.md；主题：栈利用；分类：stack。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或命令。",
"role": "user"
},
... | {
"category": "stack",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-45ee32ea3262cf2b",
"original_line": 597,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "stack.md",
"split": "train",
"split_group_key": "5d2... | pwn101_distilled_v1 | stack.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-4619919bddf289217ffb | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Kernel/CVE-2026-53362_lts/exploit/lts-6.12.85/libxdk-v0.1/xdk/util/HexDump.h` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-ae17fa99ba341bef",
"original_line": 310,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/CVE-2026-53362_lts/exploit/lts-6.12.85/lib... | pwn101_distilled_v1 | Kernel/CVE-2026-53362_lts/exploit/lts-6.12.85/libxdk-v0.1/xdk/util/HexDump.h | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-4660e998468e15e0f6ec | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「unsortedbin leak libc addr」。\n资料来源：IO-FILE/[CISCN 2022 华东北]duck/WP.md；主题：[CISCN 2022 华东北] duck - Pwn Writeup；分类：io_file。\n要求... | {
"category": "io_file",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-0956f7d4870be0d6",
"original_line": 179,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/[CISCN 2022 华东北]duck/WP.md",
"split": "train... | pwn101_distilled_v1 | IO-FILE/[CISCN 2022 华东北]duck/WP.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-469e54de4f8ab32f97b3 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「程序功能」。\n资料来源：Heap/off-by-one/2024ylb-null/WP.md；主题：2024ylb-null Writeup；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或命令... | {
"category": "heap",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-cb2715bb9366550f",
"original_line": 120,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/off-by-one/2024ylb-null/WP.md",
"split": "train",
... | pwn101_distilled_v1 | Heap/off-by-one/2024ylb-null/WP.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-47285265dc947eac0bbb | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Kernel/CVE-2026-53362_lts/exploit/lts-6.12.85/libxdk-v0.1/xdk/payloads/PayloadBuilder.h` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入... | {
"category": "kernel",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-76b70bbae96e486c",
"original_line": 300,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/CVE-2026-53362_lts/exploit/lts-6.12.85/lib... | pwn101_distilled_v1 | Kernel/CVE-2026-53362_lts/exploit/lts-6.12.85/libxdk-v0.1/xdk/payloads/PayloadBuilder.h | train | ctf_lora_sft |
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