category stringclasses 19
values | ctf_task_type stringclasses 7
values | dataset stringclasses 1
value | id stringlengths 29 29 | messages listlengths 3 3 | metadata unknown | source_dataset stringclasses 3
values | source_path stringlengths 0 93 | split stringclasses 1
value | type stringclasses 1
value |
|---|---|---|---|---|---|---|---|---|---|
misc_vuln | pwn | ctf-dataset | ctf-lora-ae4a88b2f9dd1fb6d454 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `其它漏洞/整数溢出/cpu.c` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
{
"content":... | {
"category": "misc_vuln",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-2d3671ac11332627",
"original_line": 41,
"original_split": "validation",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "其它漏洞/整数溢出/cpu.c",
"split": "train",
"s... | pwn101_distilled_v1 | 其它漏洞/整数溢出/cpu.c | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-aeea0ec066d308792fe0 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Stack/ret2dlresolve/dl_resolve_64/32位/stage6_roputils.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
... | {
"category": "stack",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-63a42338f27b23cf",
"original_line": 53,
"original_split": "validation",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Stack/ret2dlresolve/dl_resolve_64/32位/stage6_r... | pwn101_distilled_v1 | Stack/ret2dlresolve/dl_resolve_64/32位/stage6_roputils.py | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-aefcf332020985c906cd | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「利用思路」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-33f839507b191f83",
"original_line": 3,
"original_split": "validation",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_gr... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-af3123b708383270f6a7 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Stack/ret2dlresolve/dl_resolve_64/64位/stage6.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role"... | {
"category": "stack",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-f7f3a32f5447f7a7",
"original_line": 536,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Stack/ret2dlresolve/dl_resolve_64/64位/stage6.py",
... | pwn101_distilled_v1 | Stack/ret2dlresolve/dl_resolve_64/64位/stage6.py | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-b023e9eee8986724e28f | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「free_hook」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-46b42507cf3f87a3",
"original_line": 71,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_group_... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-b06ff57bd5eab8432d22 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「fix」。\n资料来源：IO-FILE/house of storm/2026ccb catchme/wp.md；主题：2026ccb catchme；分类：io_file。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中... | {
"category": "io_file",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-443e5b4d98ee2d5c",
"original_line": 234,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/house of storm/2026ccb catchme/wp.md",
"spli... | pwn101_distilled_v1 | IO-FILE/house of storm/2026ccb catchme/wp.md | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-b08be292fee01a8bc227 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「（1）节表认识」。\n资料来源：Stack/ret2dlresolve/dl_resolve_64/dl_resolve-any_gadget.md；主题：dl_resolve-any_gadget；分类：stack。\n要求：结构化说明概念、利用... | {
"category": "stack",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-92cb34a10e794bb7",
"original_line": 584,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Stack/ret2dlresolve/dl_resolve_64/dl_resolve-any_gadget.... | pwn101_distilled_v1 | Stack/ret2dlresolve/dl_resolve_64/dl_resolve-any_gadget.md | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-b0d7a6ba38651ee72db4 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「2. 泄露地址」。\n资料来源：IO-FILE/house of storm/2026ccb catchme/wp.md；主题：2026ccb catchme；分类：io_file。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保... | {
"category": "io_file",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-24793a81e0cb3476",
"original_line": 231,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/house of storm/2026ccb catchme/wp.md",
"spli... | pwn101_distilled_v1 | IO-FILE/house of storm/2026ccb catchme/wp.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-b1150722b8d74db11e76 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/off-by-one/Asis_2016_b00ks/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
... | {
"category": "heap",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-b2e3e2cea8e15793",
"original_line": 20,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/off-by-one/Asis_2016_b00ks/exp.py",
"split": ... | pwn101_distilled_v1 | Heap/off-by-one/Asis_2016_b00ks/exp.py | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-b22298cfa1cc22a7f3ea | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「tcache bin. Poison that OOB tcache entry to return __free_hook, then write system.」。\n资料来源：Heap/2024ylb-ezheap/writeup.md；主题... | {
"category": "heap",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-4cbc40cf09109199",
"original_line": 49,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/2024ylb-ezheap/writeup.md",
"split": "train",
"sp... | pwn101_distilled_v1 | Heap/2024ylb-ezheap/writeup.md | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-b22541aee948e97ec40e | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「栈迁移」。\n资料来源：stack.md；主题：栈利用；分类：stack。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或命令。",
"role": "user"
},
{
"conten... | {
"category": "stack",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-c2909200dc65142c",
"original_line": 609,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "stack.md",
"split": "train",
"split_group_key": "5d2... | pwn101_distilled_v1 | stack.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-b2f4070e74a1a1cd68f1 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「完整 exploit」。\n资料来源：Heap/off-by-one/2024ylb-null/WP.md；主题：2024ylb-null Writeup；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的... | {
"category": "heap",
"ctf_score": 34,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-5f1ff15c694370b4",
"original_line": 8,
"original_split": "validation",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/off-by-one/2024ylb-null/WP.md",
"split": "train... | pwn101_distilled_v1 | Heap/off-by-one/2024ylb-null/WP.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-b31f44e4116645fe41f5 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「如果不能跨 cache reclaim」。\n资料来源：Kernel/2026d3ctf-d3kheap2pro/README.md；主题：2026d3ctf-d3kheap2pro；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-8a6acaffd08464f2",
"original_line": 35,
"original_split": "validation",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2026d3ctf-d3kheap2pro/README.md",
"split":... | pwn101_distilled_v1 | Kernel/2026d3ctf-d3kheap2pro/README.md | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-b39e6e872f024c8dd10e | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「3. 伪造 FILE」。\n资料来源：IO-FILE/house of apple2/2024ylb futureheap/WP.md；主题：2024ylb futureheap WP；分类：io_file。\n要求：结构化说明概念、利用条件、关键... | {
"category": "io_file",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-b8f9ac4647a07427",
"original_line": 208,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/house of apple2/2024ylb futureheap/WP.md",
"... | pwn101_distilled_v1 | IO-FILE/house of apple2/2024ylb futureheap/WP.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-b4adee8b9a7ad93afb10 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「再验证自定义 cache 是否隔离」。\n资料来源：Kernel/2026d3ctf-d3kheap2pro/README.md；主题：2026d3ctf-d3kheap2pro；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构/函... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-1a5f64d3f84b6490",
"original_line": 364,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2026d3ctf-d3kheap2pro/README.md",
"split": "tr... | pwn101_distilled_v1 | Kernel/2026d3ctf-d3kheap2pro/README.md | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-b57ccab1e85b2d239dc9 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `IO-FILE/house of storm/2026ccb catchme/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": ... | {
"category": "io_file",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-3e1efe137cd5072c",
"original_line": 164,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/house of storm/2026ccb catchme/exp.py",
... | pwn101_distilled_v1 | IO-FILE/house of storm/2026ccb catchme/exp.py | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-b5f6b3499f75c663f68e | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「（1）32位dl_resolve构造模板」。\n资料来源：Stack/ret2dlresolve/dl_resolve_64/dl_resolve-any_gadget.md；主题：dl_resolve-any_gadget；分类：stack。\n... | {
"category": "stack",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-f541df9d2561a036",
"original_line": 586,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Stack/ret2dlresolve/dl_resolve_64/dl_resolve-any_gadget.... | pwn101_distilled_v1 | Stack/ret2dlresolve/dl_resolve_64/dl_resolve-any_gadget.md | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-b6a3491836ba068aa2af | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「例题」。\n资料来源：stack.md；主题：栈利用；分类：stack。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或命令。",
"role": "user"
},
{
"content... | {
"category": "stack",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-7be1755129a85863",
"original_line": 602,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "stack.md",
"split": "train",
"split_group_key": "5d2... | pwn101_distilled_v1 | stack.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-b7220e145f5aecfe9e32 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/chunk Extend and Overlapping/hitcontraning_lab13/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-7037cbc60672e806",
"original_line": 5,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/chunk Extend and Overlapping/hitcontraning_lab13... | pwn101_distilled_v1 | Heap/chunk Extend and Overlapping/hitcontraning_lab13/exp.py | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-b86c96f9655c1b45d4bb | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「kernelXDK」。\n资料来源：Kernel/CVE-2026-53362_lts/docs/exploit.md；主题：Exploit；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或命... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-1f0b5cc7a58f75a7",
"original_line": 389,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/CVE-2026-53362_lts/docs/exploit.md",
"split": ... | pwn101_distilled_v1 | Kernel/CVE-2026-53362_lts/docs/exploit.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-b96ec5aa52129e292ed4 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Kernel/CVE-2026-53362_lts/exploit/lts-6.12.85/libxdk-v0.1/xdk/payloads/RopChain.h` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、... | {
"category": "kernel",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-2298371985e1b645",
"original_line": 301,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/CVE-2026-53362_lts/exploit/lts-6.12.85/lib... | pwn101_distilled_v1 | Kernel/CVE-2026-53362_lts/exploit/lts-6.12.85/libxdk-v0.1/xdk/payloads/RopChain.h | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-b978ff2d44a68598a97f | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「通过tty_struct自身进行kROP实现RIP劫持」。\n资料来源：Kernel/QWB2018-core/tty_struct.md；主题：tty_struct；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点... | {
"category": "kernel",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-1dccfc9c637cabbe",
"original_line": 400,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/QWB2018-core/tty_struct.md",
"split": "train",... | pwn101_distilled_v1 | Kernel/QWB2018-core/tty_struct.md | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-b987fbd9dabeb25e6721 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Stack/ret2dlresolve/dl_resolve_64/32位/stage6_libc1.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
... | {
"category": "stack",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-fcdcb68bc18b1bda",
"original_line": 531,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Stack/ret2dlresolve/dl_resolve_64/32位/stage6_libc1... | pwn101_distilled_v1 | Stack/ret2dlresolve/dl_resolve_64/32位/stage6_libc1.py | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-b9d33f85765f305c762c | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「leak heap」。\n资料来源：Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md；主题：CISCN2024 华南赛区 my_heap Writeup；分类：heap。\n要求：结构化说明概念、利用条件... | {
"category": "heap",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-240f8cd67e666d7b",
"original_line": 130,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md",
"split... | pwn101_distilled_v1 | Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-ba05d84c9df69b55047d | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Kernel/xhlj2021-easykernel/start.sh` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
}... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-92854c638ffc742d",
"original_line": 331,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/xhlj2021-easykernel/start.sh",
"split": ... | pwn101_distilled_v1 | Kernel/xhlj2021-easykernel/start.sh | train | ctf_lora_sft |
misc_vuln | pwn | ctf-dataset | ctf-lora-ba11bf458d0fff0802da | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `其它漏洞/格式化字符串/blind/dump.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
{
... | {
"category": "misc_vuln",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-7178b5b6d42d0268",
"original_line": 457,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "其它漏洞/格式化字符串/blind/dump.py",
"split": "train"... | pwn101_distilled_v1 | 其它漏洞/格式化字符串/blind/dump.py | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-ba63af74fbae659000f0 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「UAF」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代... | {
"category": "heap",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-6fd6e4853840252b",
"original_line": 87,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_group_... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-bc541a7948c4b7358ddf | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「add」。\n资料来源：Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md；主题：CISCN2024 华南赛区 my_heap Writeup；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/... | {
"category": "heap",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-8f56f5ceede2b567",
"original_line": 141,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md",
"split... | pwn101_distilled_v1 | Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-bdb76645227aeef256c1 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「绕过tcache」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留... | {
"category": "heap",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-3c820063fb27ef95",
"original_line": 68,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_group_... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-befa14220ee6b002ce4f | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Kernel/CVE-2026-53362_lts/exploit/lts-6.12.85/libxdk-v0.1/xdk/payloads/Payload.h` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关... | {
"category": "kernel",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-5d56d51e0874833a",
"original_line": 299,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/CVE-2026-53362_lts/exploit/lts-6.12.85/lib... | pwn101_distilled_v1 | Kernel/CVE-2026-53362_lts/exploit/lts-6.12.85/libxdk-v0.1/xdk/payloads/Payload.h | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-bf897c28f16aa46995a9 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「AAW（RIP控制的简化版本）」。\n资料来源：Kernel/QWB2018-core/tty_struct.md；主题：tty_struct；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-dc5abf3031b3ba63",
"original_line": 403,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/QWB2018-core/tty_struct.md",
"split": "train",... | pwn101_distilled_v1 | Kernel/QWB2018-core/tty_struct.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-c12521a318cf2d47862c | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「pwndbg」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-6f59f0014245e8fb",
"original_line": 86,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_group_... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-c28c24bf6d5bb80efad0 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「函数表：pipe_buf_operations」。\n资料来源：Kernel/2022ciscn-cactus/wp.md；主题：CISCN 2022 西南赛区半决赛 cactus WP；分类：kernel。\n要求：结构化说明概念、利用条件、关键... | {
"category": "kernel",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-9917b35f36636125",
"original_line": 343,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2022ciscn-cactus/wp.md",
"split": "train",
"... | pwn101_distilled_v1 | Kernel/2022ciscn-cactus/wp.md | train | ctf_lora_sft |
misc_vuln | pwn | ctf-dataset | ctf-lora-c2ada0fff29183c395a7 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `其它漏洞/整数溢出/cpu.s` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
{
"content":... | {
"category": "misc_vuln",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-3b2086847cd75c74",
"original_line": 441,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "其它漏洞/整数溢出/cpu.s",
"split": "train",
"split... | pwn101_distilled_v1 | 其它漏洞/整数溢出/cpu.s | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-c398c80a1320f13250e6 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「2. 一次任意地址写」。\n资料来源：Heap/2024ylb-ezheap/writeup.md；主题：2024ylb-ezheap；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或命令。",
... | {
"category": "heap",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-c02d3822a240a84a",
"original_line": 54,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/2024ylb-ezheap/writeup.md",
"split": "train",
"sp... | pwn101_distilled_v1 | Heap/2024ylb-ezheap/writeup.md | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-c45b4237a1c3d95dfa06 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「2. 链表删除造成堆布局与泄露机会」。\n资料来源：IO-FILE/2025hgame hit list/WP.md；主题：2025 HGame - Hit list Writeup；分类：io_file。\n要求：结构化说明概念、利用条件、关键结... | {
"category": "io_file",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-c3299b163ed800f4",
"original_line": 174,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/2025hgame hit list/WP.md",
"split": "train",... | pwn101_distilled_v1 | IO-FILE/2025hgame hit list/WP.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-c4c51dbb65621d34ed76 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/tcache attack/house of io/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-56c4f832ced5accc",
"original_line": 29,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/tcache attack/house of io/exp.py",
"split": "... | pwn101_distilled_v1 | Heap/tcache attack/house of io/exp.py | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-c4d020227b54ce730947 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/tcache attack/Hitcon-CTF2019-one_punch_man/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
... | {
"category": "heap",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-472faa9cb8c1b04b",
"original_line": 24,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/tcache attack/Hitcon-CTF2019-one_punch_man/exp.... | pwn101_distilled_v1 | Heap/tcache attack/Hitcon-CTF2019-one_punch_man/exp.py | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-c58db9d11e4abe705aaf | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「原理」。\n资料来源：stack.md；主题：栈利用；分类：stack。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或命令。",
"role": "user"
},
{
"content... | {
"category": "stack",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-bd1371e5aef88a01",
"original_line": 608,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "stack.md",
"split": "train",
"split_group_key": "5d2... | pwn101_distilled_v1 | stack.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-c5e1a5aa5616a5f60e96 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「tcache key 绕过」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-3dc16c0a4112c670",
"original_line": 69,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_group_... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-c690f4c70cfeb4c0730d | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/tcache attack/tcache dup/patch.sh` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-9fafa2ee07b12634",
"original_line": 33,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/tcache attack/tcache dup/patch.sh",
"split": ... | pwn101_distilled_v1 | Heap/tcache attack/tcache dup/patch.sh | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-c72cdacd353849491f67 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「题目信息」。\n资料来源：Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md；主题：CISCN2024 华南赛区 my_heap Writeup；分类：heap。\n要求：结构化说明概念、利用条件、关键结构... | {
"category": "heap",
"ctf_score": 34,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-5c08b7a6985f1d89",
"original_line": 135,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md",
"split... | pwn101_distilled_v1 | Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-c82e32afc6a43d5c53e9 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「6. malloc 到 environ，泄露 stack」。\n资料来源：Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md；主题：CISCN2024 华南赛区 my_heap Writeup；分类：hea... | {
"category": "heap",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-a03e6673ef712fe6",
"original_line": 142,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md",
"split... | pwn101_distilled_v1 | Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-c8fc753a304a60f29589 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「保护信息」。\n资料来源：IO-FILE/[CISCN 2022 华东北]duck/WP.md；主题：[CISCN 2022 华东北] duck - Pwn Writeup；分类：io_file。\n要求：结构化说明概念、利用条件、关键结构/函数、... | {
"category": "io_file",
"ctf_score": 34,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-c8925471ab7f5c68",
"original_line": 185,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/[CISCN 2022 华东北]duck/WP.md",
"split": "train... | pwn101_distilled_v1 | IO-FILE/[CISCN 2022 华东北]duck/WP.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-c91d6e0365252f151548 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/fastbin attack/fastbin-double_free/[HGAME 2023 week2]new_fast_note/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-a45be7102e26f1b2",
"original_line": 8,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/fastbin attack/fastbin-double_free/[HGAME 2023 w... | pwn101_distilled_v1 | Heap/fastbin attack/fastbin-double_free/[HGAME 2023 week2]new_fast_note/exp.py | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-c953f0ca2fe2be174785 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「原理」。\n资料来源：stack.md；主题：栈利用；分类：stack。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或命令。",
"role": "user"
},
{
"content... | {
"category": "stack",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-e410c2836384e6de",
"original_line": 616,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "stack.md",
"split": "train",
"split_group_key": "5d2... | pwn101_distilled_v1 | stack.md | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-c9cb2957eddcc3315b71 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「稳定版 exp 示例」。\n资料来源：IO-FILE/[CISCN 2022 华东北]duck/WP.md；主题：[CISCN 2022 华东北] duck - Pwn Writeup；分类：io_file。\n要求：结构化说明概念、利用条件、关键... | {
"category": "io_file",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-0035e801ca3abbda",
"original_line": 178,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/[CISCN 2022 华东北]duck/WP.md",
"split": "train... | pwn101_distilled_v1 | IO-FILE/[CISCN 2022 华东北]duck/WP.md | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-ca886e1a5764ae9a3de0 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Stack/ret2shellcode/mprotect_bypass_NX/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": ... | {
"category": "stack",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-66c6c5e1f46e52e0",
"original_line": 547,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Stack/ret2shellcode/mprotect_bypass_NX/exp.py",
... | pwn101_distilled_v1 | Stack/ret2shellcode/mprotect_bypass_NX/exp.py | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-caae0f1dc9fb3e5f6a59 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「总结」。\n资料来源：IO-FILE/house of apple2/2024pcb babyheap/WP.md；主题：2024PCB babyheap WP；分类：io_file。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并... | {
"category": "io_file",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-514a9738bf688efd",
"original_line": 193,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/house of apple2/2024pcb babyheap/WP.md",
"sp... | pwn101_distilled_v1 | IO-FILE/house of apple2/2024pcb babyheap/WP.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-cad3c3a6c634e52e0ed4 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/2024ylb-ezheap/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
{
... | {
"category": "heap",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-746c092440420713",
"original_line": 2,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/2024ylb-ezheap/exp.py",
"split": "train",
"s... | pwn101_distilled_v1 | Heap/2024ylb-ezheap/exp.py | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-cc2a5ee6128d009c4d1d | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「利用思路」。\n资料来源：IO-FILE/2025hgame hit list/WP.md；主题：2025 HGame - Hit list Writeup；分类：io_file。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留... | {
"category": "io_file",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-be8816d4d75ae762",
"original_line": 172,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/2025hgame hit list/WP.md",
"split": "train",... | pwn101_distilled_v1 | IO-FILE/2025hgame hit list/WP.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-cd3f2bf3cf92a3e94181 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/tcache attack/tcache poisoning/qwqss journey_story/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-2f26e08884602e34",
"original_line": 37,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/tcache attack/tcache poisoning/qwqss journey_st... | pwn101_distilled_v1 | Heap/tcache attack/tcache poisoning/qwqss journey_story/exp.py | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-ce8da4af40983f0871eb | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `IO-FILE/2025hgame hit list/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
... | {
"category": "io_file",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-ddaeea874f3242c3",
"original_line": 153,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/2025hgame hit list/exp.py",
"split": "... | pwn101_distilled_v1 | IO-FILE/2025hgame hit list/exp.py | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-cff4ee2e780e687a4997 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「poison environ, leak pie」。\n资料来源：Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md；主题：CISCN2024 华南赛区 my_heap Writeup；分类：heap。\n... | {
"category": "heap",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-859b52b5a212f329",
"original_line": 140,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md",
"split... | pwn101_distilled_v1 | Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-d1c94286e1a306adedaa | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「leak libc」。\n资料来源：Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md；主题：CISCN2024 华南赛区 my_heap Writeup；分类：heap。\n要求：结构化说明概念、利用条件... | {
"category": "heap",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-23f2281651e645f3",
"original_line": 129,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md",
"split... | pwn101_distilled_v1 | Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-d1ea47bee89c1edc8270 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「原理」。\n资料来源：stack.md；主题：栈利用；分类：stack。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或命令。",
"role": "user"
},
{
"content... | {
"category": "stack",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-2e26d3c77de9574a",
"original_line": 593,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "stack.md",
"split": "train",
"split_group_key": "5d2... | pwn101_distilled_v1 | stack.md | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-d274304eb75d510ed6a5 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「限制条件」。\n资料来源：IO-FILE/house of storm/2026ccb catchme/wp.md；主题：2026ccb catchme；分类：io_file。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料... | {
"category": "io_file",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-2fea0d17416f859b",
"original_line": 233,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/house of storm/2026ccb catchme/wp.md",
"spli... | pwn101_distilled_v1 | IO-FILE/house of storm/2026ccb catchme/wp.md | train | ctf_lora_sft |
misc_vuln | pwn | ctf-dataset | ctf-lora-d29136c39bad9154cf44 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `其它漏洞/格式化字符串/blind/blind_fmt.c` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
{
... | {
"category": "misc_vuln",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-7513df33a78d4790",
"original_line": 456,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "其它漏洞/格式化字符串/blind/blind_fmt.c",
"split": "tr... | pwn101_distilled_v1 | 其它漏洞/格式化字符串/blind/blind_fmt.c | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-d2a3cd1e5cfabbac72dd | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「off-by-null转heap overlapping」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-5c8dcfd7a94bf42a",
"original_line": 78,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_group_... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-d2aadef5d9afda776dee | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "根据 `Heap/tcache attack/Hitcon-CTF2019-one_punch_man` 目录下的 writeup 和 exploit 示例，蒸馏一条训练样本：总结题目、漏洞点、利用链、关键代码和验证状态。",
"role": "user"
},
{
... | {
"category": "heap",
"ctf_score": 36,
"ctf_task_type": "pwn",
"original_id": "pwn101-pair-bfae94377e250cd2",
"original_line": 151,
"original_split": "train",
"record_type": "writeup_exploit_pair",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/tcache attack/Hitcon-CTF2019-one_punch_man... | pwn101_distilled_v1 | Heap/tcache attack/Hitcon-CTF2019-one_punch_man | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-d303fa2bf8e69a409084 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「2. 复用 chunk1 并伪造 chunk2 header」。\n资料来源：Heap/off-by-one/2024ylb-null/WP.md；主题：2024ylb-null Writeup；分类：heap。\n要求：结构化说明概念、利用条件、... | {
"category": "heap",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-34ba88d1e316444b",
"original_line": 114,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/off-by-one/2024ylb-null/WP.md",
"split": "train",
... | pwn101_distilled_v1 | Heap/off-by-one/2024ylb-null/WP.md | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-d3f5ca13d481b03c9afb | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「3. edit(-6) 可以覆盖 stdout FILE 结构」。\n资料来源：IO-FILE/house of apple2/2024pcb babyheap/WP.md；主题：2024PCB babyheap WP；分类：io_file。\n要... | {
"category": "io_file",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-93c7fba382b5370b",
"original_line": 197,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/house of apple2/2024pcb babyheap/WP.md",
"sp... | pwn101_distilled_v1 | IO-FILE/house of apple2/2024pcb babyheap/WP.md | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-d4da63fbd71c99c9eefb | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「利用原理」。\n资料来源：stack.md；主题：栈利用；分类：stack。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或命令。",
"role": "user"
},
{
"conte... | {
"category": "stack",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-a1d4b41637c2dae0",
"original_line": 58,
"original_split": "validation",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "stack.md",
"split": "train",
"split_group_key": ... | pwn101_distilled_v1 | stack.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-d51e106615b514d3dc01 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「1. 填满 0x100 tcache 并布置相邻 chunk」。\n资料来源：Heap/off-by-one/2024ylb-null/WP.md；主题：2024ylb-null Writeup；分类：heap。\n要求：结构化说明概念、利用条件、... | {
"category": "heap",
"ctf_score": 34,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-a1a2b60123316f7e",
"original_line": 119,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/off-by-one/2024ylb-null/WP.md",
"split": "train",
... | pwn101_distilled_v1 | Heap/off-by-one/2024ylb-null/WP.md | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-d521acd4981d69d59bda | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `IO-FILE/house of apple2/2024ylb futureheap/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"rol... | {
"category": "io_file",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-fb29e5d5d10103c1",
"original_line": 156,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/house of apple2/2024ylb futureheap/exp.p... | pwn101_distilled_v1 | IO-FILE/house of apple2/2024ylb futureheap/exp.py | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-d59aab6f3ce11b83be09 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Stack/ret2text/ret2text_x86/ret2text.c` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
... | {
"category": "stack",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-72efda54b0ff6cbd",
"original_line": 563,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Stack/ret2text/ret2text_x86/ret2text.c",
"split"... | pwn101_distilled_v1 | Stack/ret2text/ret2text_x86/ret2text.c | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-d5b6602ff7af045ed074 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「1. IDA MCP 复核的模块接口」。\n资料来源：Kernel/2026d3ctf-d3kheap2pro/ROOT_ANALYSIS.md；主题：d3kheap2pro root 提权可行性分析；分类：kernel。\n要求：结构化说明概念、... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-2994e61d1557f3bd",
"original_line": 369,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2026d3ctf-d3kheap2pro/ROOT_ANALYSIS.md",
"spli... | pwn101_distilled_v1 | Kernel/2026d3ctf-d3kheap2pro/ROOT_ANALYSIS.md | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-d5d3357c832b6672ebd2 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Stack/ret2dlresolve/2015-xdctf-pwn200/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "... | {
"category": "stack",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-cd116a2de79ae161",
"original_line": 526,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Stack/ret2dlresolve/2015-xdctf-pwn200/exp.py",
"... | pwn101_distilled_v1 | Stack/ret2dlresolve/2015-xdctf-pwn200/exp.py | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-d61dc8c6aa3ea99e3b78 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「4. 利用 overlap 做 tcache poisoning」。\n资料来源：Heap/off-by-one/2024ylb-null/WP.md；主题：2024ylb-null Writeup；分类：heap。\n要求：结构化说明概念、利用条... | {
"category": "heap",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-38c7fff02ab8a367",
"original_line": 115,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/off-by-one/2024ylb-null/WP.md",
"split": "train",
... | pwn101_distilled_v1 | Heap/off-by-one/2024ylb-null/WP.md | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-d63e1d0b50f396c6b0d7 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「漏洞点」。\n资料来源：IO-FILE/[CISCN 2022 华东北]duck/WP.md；主题：[CISCN 2022 华东北] duck - Pwn Writeup；分类：io_file。\n要求：结构化说明概念、利用条件、关键结构/函数、常... | {
"category": "io_file",
"ctf_score": 34,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-cee41605476c42bd",
"original_line": 186,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/[CISCN 2022 华东北]duck/WP.md",
"split": "train... | pwn101_distilled_v1 | IO-FILE/[CISCN 2022 华东北]duck/WP.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-d675eef7c272871ad843 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/largetbin attack/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
{
... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-9e98b0a1a015c139",
"original_line": 14,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/largetbin attack/exp.py",
"split": "train",
... | pwn101_distilled_v1 | Heap/largetbin attack/exp.py | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-d69faee95c16cf8b0789 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/unlink/2016_zctf_note2/exp_cli.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
... | {
"category": "heap",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-a04118df7ae1b09d",
"original_line": 41,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/unlink/2016_zctf_note2/exp_cli.py",
"split": ... | pwn101_distilled_v1 | Heap/unlink/2016_zctf_note2/exp_cli.py | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-d6e2160cbb224a18c02c | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「内存布局」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-fa04d012bdbc33e2",
"original_line": 110,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_group... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-d760bc466687c5efbc5a | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Stack/ret2dlresolve/dl_resolve_64/32位/stage6.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role"... | {
"category": "stack",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-cbb23051d5144413",
"original_line": 530,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Stack/ret2dlresolve/dl_resolve_64/32位/stage6.py",
... | pwn101_distilled_v1 | Stack/ret2dlresolve/dl_resolve_64/32位/stage6.py | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-d76784d8602b800e43a1 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「2. 后续提权」。\n资料来源：Kernel/2022ciscn-cactus/wp.md；主题：CISCN 2022 西南赛区半决赛 cactus WP；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料... | {
"category": "kernel",
"ctf_score": 34,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-b98792e179f846fe",
"original_line": 31,
"original_split": "validation",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2022ciscn-cactus/wp.md",
"split": "train",... | pwn101_distilled_v1 | Kernel/2022ciscn-cactus/wp.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-d78a29be563aed8b95b4 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「4. 泄露 PIE」。\n资料来源：Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md；主题：CISCN2024 华南赛区 my_heap Writeup；分类：heap。\n要求：结构化说明概念、利用条件... | {
"category": "heap",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-f47e877a6c4400fe",
"original_line": 146,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md",
"split... | pwn101_distilled_v1 | Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-d8730c968a2645c2639a | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「堆溢出」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代... | {
"category": "heap",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-63b1827063345862",
"original_line": 79,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_group_... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-d905fc9c56f20f173a07 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「分配策略」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-333c8137c27c6f86",
"original_line": 66,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_group_... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-db1d3ad688b933d5096d | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「Group drain curve」。\n资料来源：Kernel/2026d3ctf-d3kheap2pro/XCACHE_RESULTS.md；主题：d3kheap2pro cross-cache / Dirty Pagetable experi... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-da4a7224e13cd9ef",
"original_line": 385,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2026d3ctf-d3kheap2pro/XCACHE_RESULTS.md",
"spl... | pwn101_distilled_v1 | Kernel/2026d3ctf-d3kheap2pro/XCACHE_RESULTS.md | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-db4fa938c8791dbe7e9e | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「完整利用脚本」。\n资料来源：IO-FILE/2025hgame hit list/WP.md；主题：2025 HGame - Hit list Writeup；分类：io_file。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并... | {
"category": "io_file",
"ctf_score": 34,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-db47c092a2282da3",
"original_line": 177,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/2025hgame hit list/WP.md",
"split": "train",... | pwn101_distilled_v1 | IO-FILE/2025hgame hit list/WP.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-db71a4134ebe9f590017 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「PoC」。\n资料来源：Kernel/2022ciscn-cactus/wp.md；主题：CISCN 2022 西南赛区半决赛 cactus WP；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码... | {
"category": "kernel",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-2dfc570e90d29940",
"original_line": 337,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2022ciscn-cactus/wp.md",
"split": "train",
"... | pwn101_distilled_v1 | Kernel/2022ciscn-cactus/wp.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-dc0482be3b0c42185ca2 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「7. 恢复 hidden backdoor 使用次数」。\n资料来源：Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md；主题：CISCN2024 华南赛区 my_heap Writeup；分类：heap。... | {
"category": "heap",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-d671564b65a72359",
"original_line": 144,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md",
"split... | pwn101_distilled_v1 | Heap/tcache attack/ciscn2024_华南赛区-myheap/WP.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-dd25d3206ac8ccfdc7e1 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Heap/tcache attack/tcache绕过/patch.sh` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-16abf10f40d508cd",
"original_line": 38,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/tcache attack/tcache绕过/patch.sh",
"split": "t... | pwn101_distilled_v1 | Heap/tcache attack/tcache绕过/patch.sh | train | ctf_lora_sft |
misc_vuln | pwn | ctf-dataset | ctf-lora-dd2d2252498cab91bd7a | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `其它漏洞/条件竞争/racetest/demo.c` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
{
... | {
"category": "misc_vuln",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-aad6456045b18df3",
"original_line": 450,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "其它漏洞/条件竞争/racetest/demo.c",
"split": "train"... | pwn101_distilled_v1 | 其它漏洞/条件竞争/racetest/demo.c | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-dd362389411d8eb76fa6 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「Search result」。\n资料来源：Kernel/2026d3ctf-d3kheap2pro/WEB_REFERENCE_NOTES.md；主题：Internet reference notes for d3kheap2pro；分类：ker... | {
"category": "kernel",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-4e6336fb14438bfd",
"original_line": 377,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2026d3ctf-d3kheap2pro/WEB_REFERENCE_NOTES.md",
... | pwn101_distilled_v1 | Kernel/2026d3ctf-d3kheap2pro/WEB_REFERENCE_NOTES.md | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-de48701ecb9b6b2e701f | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「调用GetSize函数来获取密码长度」。\n资料来源：stack.md；主题：栈利用；分类：stack。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码块或命令。",
"role": "user"
},
... | {
"category": "stack",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-2bc6c2d04fbe73ee",
"original_line": 592,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "stack.md",
"split": "train",
"split_group_key": "5d2... | pwn101_distilled_v1 | stack.md | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-deb73b8c3e2eb8ec6ac1 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「tcache poisoning」。\n资料来源：IO-FILE/2025hgame hit list/WP.md；主题：2025 HGame - Hit list Writeup；分类：io_file。\n要求：结构化说明概念、利用条件、关键结构... | {
"category": "io_file",
"ctf_score": 34,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-b82186f384b96c5e",
"original_line": 170,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/2025hgame hit list/WP.md",
"split": "train",... | pwn101_distilled_v1 | IO-FILE/2025hgame hit list/WP.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-df9c4ba047417661b946 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Kernel/2026d3ctf-d3kheap2pro/exp.c` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},... | {
"category": "kernel",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-d3c3118f54960547",
"original_line": 288,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2026d3ctf-d3kheap2pro/exp.c",
"split": "... | pwn101_distilled_v1 | Kernel/2026d3ctf-d3kheap2pro/exp.c | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-e04912bc3ae6a8032a39 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「1. 覆盖 seed，预测 rand」。\n资料来源：IO-FILE/house of apple2/2024ylb futureheap/WP.md；主题：2024ylb futureheap WP；分类：io_file。\n要求：结构化说明概念... | {
"category": "io_file",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-8a93be9e0785506e",
"original_line": 205,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/house of apple2/2024ylb futureheap/WP.md",
"... | pwn101_distilled_v1 | IO-FILE/house of apple2/2024ylb futureheap/WP.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-e113f8078b7c0415798a | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Kernel/2024wdb/server.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},
{
"... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-f419f1040838a205",
"original_line": 283,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2024wdb/server.py",
"split": "train",
... | pwn101_distilled_v1 | Kernel/2024wdb/server.py | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-e25f98a00024bf6e8518 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Kernel/2026d3ctf-d3kheap2pro/make_autorun_image.sh` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"ro... | {
"category": "kernel",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-a21f4309d2b19f4a",
"original_line": 290,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2026d3ctf-d3kheap2pro/make_autorun_image.s... | pwn101_distilled_v1 | Kernel/2026d3ctf-d3kheap2pro/make_autorun_image.sh | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-e28bb1868c1e8f3c428f | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Stack/花式栈/2025hgame ezstack/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
},... | {
"category": "stack",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-714861edceeecd5a",
"original_line": 576,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Stack/花式栈/2025hgame ezstack/exp.py",
"split": "t... | pwn101_distilled_v1 | Stack/花式栈/2025hgame ezstack/exp.py | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-e2eef63457f7e7ef314e | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「地址泄露」。\n资料来源：IO-FILE/2025hgame hit list/WP.md；主题：2025 HGame - Hit list Writeup；分类：io_file。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留... | {
"category": "io_file",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-763e303731060cb7",
"original_line": 168,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/2025hgame hit list/WP.md",
"split": "train",... | pwn101_distilled_v1 | IO-FILE/2025hgame hit list/WP.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-e32dbbf620a912b24267 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「模块接口」。\n资料来源：Kernel/2026d3ctf-d3kheap2pro/README.md；主题：2026d3ctf-d3kheap2pro；分类：kernel。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-de99054d7cbb4980",
"original_line": 37,
"original_split": "validation",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/2026d3ctf-d3kheap2pro/README.md",
"split":... | pwn101_distilled_v1 | Kernel/2026d3ctf-d3kheap2pro/README.md | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-e379f90180637c035878 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「2.1 初始化与信息泄露」。\n资料来源：IO-FILE/house of apple2/2024ylb futureheap/WP.md；主题：2024ylb futureheap WP；分类：io_file。\n要求：结构化说明概念、利用条件、... | {
"category": "io_file",
"ctf_score": 30,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-319a5ccfbce55aea",
"original_line": 200,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/house of apple2/2024ylb futureheap/WP.md",
"... | pwn101_distilled_v1 | IO-FILE/house of apple2/2024ylb futureheap/WP.md | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-e3b32ad65ea08385337e | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「原理」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的代码... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-658f4cfafba4a653",
"original_line": 81,
"original_split": "train",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_group_... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
kernel | pwn | ctf-dataset | ctf-lora-e49ce97e7c0790cf5e37 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Kernel/CVE-2026-53362_lts/exploit/lts-6.12.85/libxdk-v0.1/xdk/target/TargetDb.h` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键... | {
"category": "kernel",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-79bb87917441762a",
"original_line": 309,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Kernel/CVE-2026-53362_lts/exploit/lts-6.12.85/lib... | pwn101_distilled_v1 | Kernel/CVE-2026-53362_lts/exploit/lts-6.12.85/libxdk-v0.1/xdk/target/TargetDb.h | train | ctf_lora_sft |
heap | pwn | ctf-dataset | ctf-lora-e5736d3c806d44a16d15 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "请讲解 CTF pwn/二进制安全知识点「bins」。\n资料来源：Heap/heap exploit.md；主题：define TCACHE_MAX_BINS 64；分类：heap。\n要求：结构化说明概念、利用条件、关键结构/函数、常见坑点，并保留材料中的... | {
"category": "heap",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-doc-6dbc9364d0b7ce96",
"original_line": 4,
"original_split": "validation",
"record_type": "doc_section",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Heap/heap exploit.md",
"split": "train",
"split_gr... | pwn101_distilled_v1 | Heap/heap exploit.md | train | ctf_lora_sft |
stack | pwn | ctf-dataset | ctf-lora-e5d8858564016b7e9cb8 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `Stack/srop/rootersctf_2019_srop/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": "user"
... | {
"category": "stack",
"ctf_score": 28,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-ea206faafdbe103d",
"original_line": 570,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "Stack/srop/rootersctf_2019_srop/exp.py",
"split"... | pwn101_distilled_v1 | Stack/srop/rootersctf_2019_srop/exp.py | train | ctf_lora_sft |
io_file | pwn | ctf-dataset | ctf-lora-e5fd4d24e620ea5b5b12 | [
{
"content": "你是 CTF pwn、Linux kernel exploit 与二进制安全训练数据蒸馏助手。回答必须基于给定本地材料，保留关键路径、函数名、偏移、保护信息、利用原语和验证状态；不要编造材料中没有出现的事实。",
"role": "system"
},
{
"content": "解释 `IO-FILE/house of cat/强网杯2022houseofcat/exp.py` 这个 CTF pwn/kernel exploit 代码示例的结构。请指出运行环境、交互封装、泄漏/写入/触发阶段、关键常量，以及代码适合训练模型学习的模式。",
"role": ... | {
"category": "io_file",
"ctf_score": 32,
"ctf_task_type": "pwn",
"original_id": "pwn101-code-178842e0affe08be",
"original_line": 159,
"original_split": "train",
"record_type": "code_explanation",
"source_dataset": "pwn101_distilled_v1",
"source_path": "IO-FILE/house of cat/强网杯2022houseofcat/exp.py",
... | pwn101_distilled_v1 | IO-FILE/house of cat/强网杯2022houseofcat/exp.py | train | ctf_lora_sft |
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