TITLE: q-analog of the matrix exponential
QUESTION [5 upvotes]: I am a fan of the Matrix exponential $\exp(X)$, defined for any complex matrix $X$ by 
\begin{equation*}
 \exp(X) := \sum_{k \ge 0} \frac{X^k}{k!}.
\end{equation*}
I have a fleeting acquaintance with q-analog's (essentially, I know that they exist, but have almost no idea what use they serve, which is part of the reason why I am asking this question).
Thus, my question is

Has the following q-analog of the matrix exponential
  \begin{equation*}
 \exp_q(X) := \sum_{k \ge 0} \frac{X^k}{[k]_q!},
\end{equation*}
  been studied previously? If so, in what context?


PS: More generally, the above question can be rephrased in terms of q-analogs of functions of matrices (which includes scalar, vector, and matrix valued functions). But I wanted to limit my focus to a concrete case of special interest to me.

REPLY [8 votes]: It's more an example than a general answer. Details can be found here : http://arxiv.org/abs/math/0512500
It is convenient to replace $q$ by $q^2$ in the formula that you gave. Doing so we have the following desirable identities:

$\exp_q(x)\exp_{-q}(-x)=1$
if $xy=q^2yx$, then $\exp_q(y)\exp_q(x)=\exp_q(x+y)$

Now if $\mathfrak g$ is a simple Lie algebra, $\Phi^+$ a choice of positive roots, $h_i,e_{\alpha},f_{\alpha}$ the generators of $U_q(\mathfrak g)$ associated to the Chevalley basis of $\mathfrak g$, $>$ a normal ordering on $\Phi^+$, and $q_{\alpha}=q^{(\alpha,\alpha)/2}$, then the R-matrix of $U_q(\mathfrak g)$ is given by
$$
R=K \prod_{\alpha \in \Phi^+}^> R_{\alpha}
$$
where 
$$K=q^{\sum h_i \otimes h^i}$$
and
$$R_{\alpha}=\exp_{q_{\alpha}^{-1}}((q_{\alpha}-q_{\alpha}^{-1})e_{\alpha} \otimes f_{\alpha})$$
Here $q$ is either a generic complex number, or a variable, in which case we work over the field $\mathbb{Q}(q^{\frac12})$.
It is a universal formula, but of course you can specialize it to an element of $End(V\otimes V)$ for any $U_q(\mathfrak g)$-module $V$.