TITLE: What is the geometric interpretation of a vector squared?
QUESTION [7 upvotes]: I'm working through Introduction to Space Dynamics by William Tyrrell Thomson. I am having to do a lot of research to make it through even small parts, but I am unable to find information to make me confident enough to solve this question from the book:

What is the geometric interpretation of $\left(\vec{a} + \vec{b}\right)^2$?

To start, I'm considering a simplified form: $\vec{c}^2, c = \vec{a} + \vec{b}$
This is where I get stuck, as I have not been able to find how to handle a vector multiplied by itself. Information one place states that a vector multiplied by itself is the same as the dot product of a vector with itself: $\vec{c}\cdot\vec{c}$. Other places I've found information which makes me think that multiplying a vector by another vector in the sense one would multiply a scalar by a scalar is not a valid operation to perform.
Which of these two is the case, or is it a third case I haven't considered?
Am I approaching the problem incorrectly?

REPLY [3 votes]: $\vec{c}^2$ is an alternative notation for $\vec{c}\cdot\vec{c}=||\vec{c}||^2$
A motivation for this is that the formulas 
$$||\vec{a}+\vec{b}||^2=||\vec{a}||^2+2\vec{a}\cdot\vec{b}+||\vec{b}||^2$$
$$||\vec{a}-\vec{b}||^2=||\vec{a}||^2-2\vec{a}\cdot\vec{b}+||\vec{b}||^2$$
and
$$(\vec{a}+\vec{b})\cdot(\vec{a}-\vec{b})=||\vec{a}||^2-||\vec{b}||^2$$
now becomes
$$(\vec{a}+\vec{b})^2=\vec{a}^2+2\vec{a}\cdot\vec{b}+\vec{b}^2$$
$$(\vec{a}-\vec{b})^2=\vec{a}^2-2\vec{a}\cdot\vec{b}+\vec{b}^2$$
and
$$(\vec{a}+\vec{b})\cdot(\vec{a}-\vec{b})=\vec{a}^2-\vec{b}^2$$
Similarities with the corresponding scalar identities make them easier to remember.