TITLE: Uniqueness of determinant
QUESTION [14 upvotes]: In Artin Algebra 2nd edition page 22, the author proved the uniqueness of determinant by saying that any matrix $A$ can be written in reduced row-echelon form $A'$: $A'=E_1\cdots E_kA$ where $E_i$ are the elementary matrix. Then $A'$ is either $I$ or has a zero row. If $A'=I$, then $\delta(A')=1$. Otherwise, $\delta(A')=0$. In both cases, $\delta(A')$ is determined, and hence by
$$\delta(A')=\delta(E_1)\cdots\delta(E_k)\delta(A)$$
$\delta(A)$ is determined uniquely.
However, as he himself pointed out immediately in the following paragraph, the sequence $E_1\cdots E_k$ is not unique. Then why is $\delta(A)$ uniquely determined?
Edit:
The author defined determinant as a function $\delta(A)=d\in \mathbb{R}$ satisfying the following 3 conditions:
(i) $\delta(I)=1$
(ii) $\delta$ is linear in the rows of the matrix $A$
(iii) If two adjacent rows of $A$ are equal, then $\delta(A)=0$
He then proved that the above conditions imply some properties that all of us know, e.g.,
(a) Interchanging two rows reverses the sign
(b) If $A$ has a zero row, then $\delta(A)=0$
(c) Multiplying one row by a number and adding it to another row doesn't change the determinant
(d) $\delta(E)=\pm1$ or $c$
(e) $\delta(AB)=\delta(A)\delta(B)$
Then he proved that the function $\delta$ so defined is unique, as shown in the beginning of my post, which I don't understand

REPLY [2 votes]: The proof mentioned in the first paragraph of the question is not the proof for uniqueness of the Determinant Function. It says: The determinant of a matrix A, det (A), can be determined from determinant of it's row reduced form det (A'). It just says it can be determined. As you mentioned, the Author also clarifies that since the product of elementary matrices can be written in many ways, uniqueness can't be proved in this way. So, the uniqueness proof is yet incomplete.
When the Author starts off the Determinants topic, he mentions:
"The determinants of an nxn matrix is a functions of it's $n^2$ entries. There is one such function for each positive integer n. Unfortunately, there are many formulas for these determinants and all of them are complicated when n is large. Not only are the formulas complicated, but it may not be easy to show that two of them define the same function.
We use the following strategy: We choose one of the formulas, and take it as our definition of the determinant. In that way we are talking about a particular function. We show that our chosen function is the only one having certain special properties. Then, to show that other formula defines the same determinant function, one needs only to check those properties for the other function. This is often not too difficult."
Using the above statements, to prove the uniqueness, the author goes ahead to prove that the chosen standard determinant function (which is the expansion of minors on the first column) satisfies the properties of a Determinant function.
The way this proof is done: Using induction on the size of the matrices. We know that the properties are true for 1x1 matrices. Assuming that the properties are true for determinant of (n-1)x(n-1) matrices, we prove for nxn matrix. This completes the uniqueness proof.