TITLE: When is $\mathrm{Proj}(A)$ projective?
QUESTION [7 upvotes]: We consider the scheme $P:=\mathrm{Proj}(S)$ of a commutative, (nonnegatively) graded, finitely generated $\mathbb C$-algebra $S$ with no nilpotents.
(Q1) When is $P$ a projective variety?
Since we have a projective map $P \to \mathrm{Spec}(S_0)$, $P$ is projective if $S_0=\mathbb C$. But the opposite direction is too difficult for me. (I have neither a proof nor a counterexample.)
(Q2) Is $P$ always quasi-projective?
The examples which I know are always quasi-projective, so I suspect that $P$ is always quasi-projective, but I can not find any relevant references.
EDIT (An example of non-projective $P$)
Let $G = \lbrace \mathrm{diag}(t,t^{-1},u) \in GL_3(\mathbb C) | t \in \mathbb C^*, u = \pm 1 \rbrace$ act on $\mathbb C^3$ and define a character of $G$ by $\chi(t,t^{-1},u)=tu$. The character defines a $G$-equivariant line budle $L \to \mathbb C^3$. Put $$S_* = \bigoplus_{d\geq0}H^0(\mathbb C^3,L^{\otimes d})^G.$$ We can show that $S_*$ is a finitely generated $\mathbb C$-algebra (e.g. Lemma 14.1.10) and 
$$S_{2*} = \bigoplus_{d} S_{2d} = \mathbb C[xy,z^2][x^2].$$
Therefore
$$\mathrm{Proj}(S_*) = \mathrm{Proj}(S_{2*}) = \mathrm{Proj}(\mathbb C[xy,z^2][x^2]) = \mathrm{Spec}(\mathbb C[xy,z^2]) \times \mathbb P^0 = \mathbb C^2.$$
Note: This example can be found the book linked above (in Chap. 14).

REPLY [2 votes]: This answer your question just partially.
Let $S=\oplus_{n=0}^\infty S_n$ be a finitely generated graded $\mathbb{C}$-algebra and consider the graded $\mathbb{C}$-algebra $S'$ defined by $S_0'=\mathbb{C}$ and $S_n'=S_n$ for $n>0$. Then there exists an isomorphism of $\mathbb{C}$-schemes $\operatorname{Proj}(S)\cong\operatorname{Proj}(S')$ (EGA II, 2.4.8). Therefore if $S'$ is finitely generated $\mathbb{C}$-algebra then $\operatorname{Proj}(S)$ is projective.
However the condition on $S'$ of being finitely generated is not necessary because of the following: For $d>0$, let $S'^{(d)}$ be the graded $\mathbb{C}$-algebra defined by $S'^{(d)}_n=S'_{nd}$ for $n\geq 0$. Then there exists an isomorphism of $\mathbb{C}$-schemes $\operatorname{Proj}(S')\cong\operatorname{Proj}(S'^{(d)})$ (EGA II, 2.4.7).
Then we can conclude that if for some $d>0$ the $\mathbb{C}$-algebra $S'^{(d)}$ is finitely generated then $\operatorname{Proj}(S)$ is a projective variety.
For an example where $\operatorname{Proj}(S)$ is not a projective variety, I would try with $S=\mathbb{C}[X][Y]=\oplus_{n=0}^\infty \mathbb{C}[X]Y^n$. Not that in this case none of the $S'^{(d)}$ are finitely generated. I am not sure if it will work.