TITLE: Does the Riemann tensor encode all information about the second derivatives of the metric?
QUESTION [5 upvotes]: In answer to this question I suggested the following as a motivation for the definition of the Riemann tensor:

Let $\mathcal M$ and $\mathcal N$ be two dim-$n$ Lorentzian
  manifolds with points $x\in\mathcal M$ and $y\in\mathcal N$. Then you
  can pick local coordinates on $\mathcal M$ and $\mathcal N$ such that
  the expressions for $g_{\mu\nu}$ agree to second order near $x$ and
  $y$ iff you can find bases at $x$ and $y$ such that the Riemann
  tensors are equal.

Is the preceding theorem in fact true? Where can I find a proof of it?

REPLY [5 votes]: Here is a reference for Riemannian manifolds. The theorem (4.1) is that the Taylor expansion of a Riemannian metric $g$ in coordinates has the form
$$ g_{ij} = \delta_{ij} - \frac{1}{3}R_{ikjl}x^kx^l - \frac{1}{6}\nabla_m R_{ikjl}x^kx^lx^m + O(x^4). $$
This is surely also true in the pseudo-Riemannian setting. O'Neill's book probably has this stated and proved somewhere in the first several chapters. I don't have it handy at the moment but will verify when I get home.