TITLE: Measure 11 liters using bottles of 16, 6, and 3 liters
QUESTION [6 upvotes]: This question has been bugging me for a day and finally I gave up and decided to ask the community for it so here's how it goes: 
Suppose we have 3 bottles with capacities of $16,6$ and $3$ liters, all of which are full of water currently.
In what way can we move the water from a bottle to another one (spilling is also an option) that only $11$ liters of water remain in the $16$-liter bottle?
EDIT:Thanks for your comments and now I believe you may have misinterpreted my question and therefore I think I'll unmark the answer for now(which I realized was not true after a while).
EDIT2:I forgot to mention the following conditions but they pretty much could be interpreted from the question iteself:

We cannot measure a bottle half-way.
The only scales we have are only these 3 bottles (This one is more like an emphasize on the first condition but anyway I needed to add it)
There's no reservoir where we can keep the spilled water.
There are no other water resources from which we can add water.

and finally I need to point out the fact that the question may or may NOT have an answer so it's more like a "prove or disprove" kind of question.
EDIT3:Multiple transfers are allowed (Thanks to @David for pointing it out)
Thanks for your help in advance.

REPLY [2 votes]: I'm going to assume that the allowable operations are:

empty a bottle completely; and 
empty one bottle into another until the former is empty or the latter is full, whichever happens first.

Then this graph shows the shortest path to reach any reachable state (click here for a full-size version with readable labels):

No state with a bottle containing 11 (or 2, 5, 8, 12, 14, or 15) liters is reachable.