TITLE: Construction of non-prime finite fields
QUESTION [5 upvotes]: I am new to Galois field theory and I am struggling with some definitions. To construct any non-prime finite field $GF(p^n)$ with p prime and $n \in \mathbb{N}$, one has to find an irreducible polynomial $g(x)$ in $GF(p)$ and eventually calculate $GF(p^n) = G(p)[x] / g(x)$.
Assuming I want to construct $GF(9) = GF(3^2)$. Why do I have to do the stuff  above? Doesn't $GF(3^2)$ simply contains elements ranging from 0 to 8? What is the upper construction rule about?

REPLY [5 votes]: The only finite fields that equal the rings $\Bbb Z/n\Bbb Z$ are the ones where $n$ is a prime.  Because if $n=ab$ then $\overline{a}\cdot\overline{b}=\overline{0}$ in  $\Bbb Z/n\Bbb Z$ and we know that can't happen in a field.  On the other hand if you adjoin a root of an irreducible polynomial of degree $2$ to $\Bbb Z/3\Bbb Z$ then you get a degree two extension of $\Bbb Z/3\Bbb Z$ which has nine elements, but is not equal to $\Bbb Z/9\Bbb Z$.