TITLE: What is $\operatorname{Spec}\mathbf{C}[[x,y]]/(y^{2} - x^{3} - x^{2})$?
QUESTION [20 upvotes]: Let $X = \operatorname{Spec} \mathbf{C}[[x,y]]/(y^{2} - x^{3} - x^{2})$. I would like to describe $X$ set-theoretically. My questions are: Can one explicitly say what the elements in $X$ are? Is it possible to interpret them geometrically? And is $X$ irreducible? 
I am not really sure where to get started. Any help would be much appreciated.

REPLY [31 votes]: Geometrically you are considering germ of singular node at the origin, that is at the singularity. The node is  $  N = \textrm{Spec} ( \mathbf{C}[x,y]/(y^{2} - x^{3} - x^{2})) $  and is irreducible affine curve, because polynomial $y^{2} - x^{3} - x^{2}$ is irreducible in polynomial ring  $\mathbf{C}[x,y]$. However your germ $X$ is reducible: this is because polynomial $y^{2} - x^{3} - x^{2}$ become reducible in formal powers series ring : $\; y^{2} - x^{3} - x^{2}=(y-x\sqrt{1+x})(y+x\sqrt{1+x})\in \mathbf{C}[[x,y]]$
 where $\sqrt{1+x}= 1+\frac{1}{2}x+...$ can be developed by Newton binomial in 
$\mathbf{C}[[x,y]]$.
So in scheme sense $X$ contains three points:  origin (= singularity )and two generic points of two irreducible components of $N$. 
This is very intersting because node remains irreducible in every neighbourhood of origin in affine plane  $\textrm{Spec} ( \mathbf{C}[x,y])$ but by going to formal series you obligate curve to split in two components. So intuition should be that going to formal series is strong form of localization.