TITLE: When is it true that $\dim(U \cap (V+W))=\dim(U \cap V + U \cap W)$?
QUESTION [5 upvotes]: I apologize if this is a silly question( which may have been asked before), I was wondering after seeing a post on this list on math-overflow

When is it true that $\dim(U \cap (V+W))=\dim(U \cap V + U \cap W$)?
This is not true in general, since we can set $U,V,W$ to be three distinct lines in $\mathbb{R}^{2}$. For example, if if I set $U=\langle (1,0)\rangle$, $V=\langle (0,1)\rangle$, and $W=\langle (1,1) \rangle$. We then have that
$\dim(U \cap (V+W))=\dim(U)=1$
$\dim(U \cap V + U \cap W)=0$
I was just curious more than anything.

REPLY [3 votes]: Since $U\cap (V+W)$ and $(U\cap V)+(U\cap W)$ are both vector spaces, with the former containing the latter, they have the same dimension exactly when they are equal.  Hence, the original question is true precisely when $$U\cap ((V+W)\setminus V\setminus W)=\emptyset$$
In the example given, $(1,0)\in U\cap ((V+W)\setminus V\setminus W)$.