TITLE: Nested Sequence of Non-Empty Compact Sets
QUESTION [5 upvotes]: Let $K_n$ be a nested sequence of non-empty compact sets in a Hausdorff space.
Prove that if an open set $U$ contains contains their (infinite) intersection, then there exists an integer $m$ such that $U$ contains $K_n$ for all $n>m$.
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(I know that compact sets are closed in Hausdorff spaces. I can also prove that the infinite intersection of non-empty compact sets is non-empty, closed and compact in a Hausdorff space. I don't know how to use the fact that U is open.)

REPLY [5 votes]: Assume the contrary, that $V_{n}:=K_{n}\cap U^{c}\neq \emptyset$ for all $n$. Each $V_{n}$ is compact, since $U$ is open, and non-empty, so the intersection $\bigcap_{n} V_{n}$ is non-empty as well. But $\bigcap_{n}V_{n}=(\bigcap_{n}K_{n})\cap U^{c}\subset U\cap U^{c}=\emptyset$, which is a contradiction. Hence there exists $m$ such that $V_{n}=\emptyset$ for all $n>m$, whence $K_{n}\subset U$ for all $n>m$.