TITLE: Find the definite integral
QUESTION [7 upvotes]: Find the definite integral
$$\int_{1}^{2}\frac{(3x-1)(2x+3)}{x} dx$$
I have come to an answer of $16 - \ln(8)$ which I think is very wrong..
First used integration by  parts

REPLY [2 votes]: expanding the integrad and dividing by $x$ we get $$\int_{1}^{2}7+6x-\frac{3}{x}dx$$
the indefinite integral is given by $$7x+3x^2-3\ln|x|+C$$