TITLE: An infinite dictionary: countably infinite or uncountably infinite?
QUESTION [7 upvotes]: This question concerns Ian Stewart's "Hyperwebster", an uncountable dictionary. 
Say a publishing company wants to publish every possible permutation (of any length) of the characters A-Z. The dictionary might look like this:
A, AA, AAA, ..., AB, ABA, ABAA, ..., AC, ..., AZ, AZA, ...
B, BA, BAA, ..., BB, BBA, BBAA, ..., BC, ..., BZ, BZA, ...
C, CA, CAA, ..., CB, CBA, CBAA, ..., CC, ..., CZ, CZA, ...
Z, ZA, ZAA, ..., ZB, ZBA, ZBAA, ..., ZC, ..., ZZ, ZZA, ...
The publishing company realizes that the dictionary can be reorganized into 26 volumes, with each volume corresponding to one of the 26 characters:

Volume A: A, AA, AAA, ..., AB, ABA, ABAA, ..., AC, ..., AZ, AZA, ...
Volume B: B, BA, BAA, ..., BB, BBA, BBAA, ..., BC, ..., BZ, BZA, ...
Volume C: C, CA, CAA, ..., CB, CBA, CBAA, ..., CC, ..., CZ, CZA, ...
Volume Z: Z, ZA, ZAA, ..., ZB, ZBA, ZBAA, ..., ZC, ..., ZZ, ZZA, ...

The company can save some ink by dropping the first letter, since it can be inferred from each of the 26 volumes.

Volume A: A, AA, AAA, ..., B, BA, BAA, ..., C, ..., Z, ZA, ...
Volume B: A, AA, AAA, ..., B, BA, BAA, ..., C, ..., Z, ZA, ...
Volume C: A, AA, AAA, ..., B, BA, BAA, ..., C, ..., Z, ZA, ...
Volume Z: A, AA, AAA, ..., B, BA, BAA, ..., C, ..., Z, ZA, ...

Since each volume is now identical, the company decides to publish only the first volume, which is the same as the list we started with. 
In the linked article, the author remarks that this is an analogy of the real line. Can someone explain how this dictionary is uncountably infinite? Is it because of the fact that we can keep repeating the above steps, subdividing our dictionary infinitely many times, each time arriving at a set the same size as the one we started with?

REPLY [2 votes]: I have Dr. Stewart's 1996 edition of "from here to infinity" in front of me now. He nowhere explicitly says that the words are of finite length nor does he explicitly say infinite length strings are allowed. However he does say "... the analogy is closer than might appear, because the Banach-Tarski paradox is proven by using sequences of rigid motions in much the same way as I have used sequences of letters". Now if you look at a proof of the Banach-Tarski theorem you'll see that it uses FINITE sequences of rotations of the 2-sphere (based on Hausdorff's paradoxical decomposition of the 2-sphere). To me that makes it very clear that Dr. Stewart meant to define the hyperwebster as all strings of finite length. And hence the hyperwebster is countable.
But I have a problem with the common description of the hyperwebster. It's often described as
A, AA, AAA, ..., AB, ABA, ABAA, ..., AC, ..., AZ, AZA, ... B, BA, BAA, ..., BB, BBA, BBAA, ..., BC, ..., BZ, BZA, ... Z, ZA, ZAA, ..., ZB, ZBA, ZBAA, ..., ZC, ..., ZZ, ZZA, ...
Where is AAB in this list?
In fact alphabetical ordering (i.e., lexicographic ordering) is not a well ordering of the finite strings over 26 characters. See lexicographic ordering is not a well ordering.
That makes it hard to write out a complete list of the hyperwebster in alphabetical order even using ... .
A better way is alphabetical within groups of increasing string length:
a,b, ... z
aa,ab, ..., az, ba, ..., bz, ... za, ... zz
aaa, ..., zzz, ...
Now volume A is:
a, aa, ..., az, aaa, ..., azz, aaaa, ..., azzz, ...
And you can see that removing the first a in each of these gives you the original full list.