TITLE: Is there a way to check the correctness of your answer to a probability question?
QUESTION [7 upvotes]: In CS, there's a systematic way to check if your code is buggy or not as you write code. Is there a way to check the correctness of your answer to a probability question without using a textbook?
For example, my friend proposed a solution to a probability question that seemed right.
Question: Suppose that each of N men at a party throws his hat into the center of the room. The hats are first mixed up, and then each man randomly selects a hat. What is the probability that none of the men selects his own hat?
Proposed Solution: if we suppose there are 8 men, then the suggestionw as (7 / 8) * (6 / 7) * (5 /6 )... * (1/2) * 1
which for the n case simplifies to 1/n
The argument sounded reasonable, but the answer was wrong which I found out from the textbook. I had to think about it a bit before I realized he had undercounted. Is there a more systematic way to check answers for probability questions?

REPLY [7 votes]: One thing that is sometimes helpful is to write a computer program to run a lot of random trials and see if the number produced by the computer is way off the number you expect. For example:

# This is a Perl program

my $hats = shift || 8;
my $trials = shift || 10000;

my $derangements = 0;
TRIAL:
for (1..$trials) {
  my @perm = ("dummy", permute(1..$hats));
  for $hat (1..$hats) {
    if ($perm[$hat] == $hat) { next TRIAL }
  }
  $derangements++;
}

print "In $trials trials, there were $derangements cases in which nobody got their own hat.\n";
printf "That's %5.2f%%.\n", $derangements * 100 / $trials;

sub permute {
  my @items = @_;
  # Fischer-Yates algorithm
  for my $n (reverse 0 .. $#items) {
    my $m = int rand($n + 1);
    @items[$n,$m] = @items[$m,$n] if $m != $n;
  }
  return @items;
}

This prints:

In 10000 trials, there were 3683 cases in which nobody got their own hat.
That's 36.83%.

This is far enough from your suggested value of $\frac78\frac67\ldots\frac12 = \frac18 = 12.5\%$ that we can be sure that that is wrong or that the program has a severe error.
(In fact, 36.83% is close to the theoretically correct value, which happens to be $2119\over 5760$.)