TITLE: How can we produce another geek clock with a different pair of numbers?
QUESTION [20 upvotes]: So I found this geek clock and I think that it's pretty cool.

I'm just wondering if it is possible to achieve the same but with another number.
So here is the problem: 
We want to find a number $n \in \mathbb{Z}$ that will be used exactly $k \in \mathbb{N}^+$ times in any mathematical expresion to produce results in range $[1, 12]$. No rounding, is allowed, but anything fancy it's ok. 
If you're answering with an example then use one pair per answer.
I just want to see that clock with another pair of numbers :)
Notes for the current clock:
1 o'clock: using 9 only twice, but it's easy to use it 3 times with many different ways. See comments.
5 o'clock: should be $\sqrt{9}! - \frac{9}{9} = 5$

REPLY [3 votes]: For $n=3$ and $k = 3$.
$1 = 3^{3-3}$
$2 = 3-\frac{3}{3}$
$3 = 3+3-3$
$4 = 3+\frac{3}{3}$
$5 = 3!-\frac{3}{3}$
$6 = 3*3-3$
$7 = 3!+\frac{3}{3}$
$8 = \pi(3)*\pi(3)*\pi(3)$
$9 = 3+3+3$
$10 = 3!+\pi(3)+\pi(3)$
$11 = 3!+3+\pi(3)$
$12 = 3*3+3$