TITLE: Evaluating  $ \int_1^{\infty} \frac{\{t\} (\{t\} - 1)}{t^2} dt$
QUESTION [9 upvotes]: I am interested in a proof of the following.
$$ \int_1^{\infty} \dfrac{\{t\} (\{t\} - 1)}{t^2} dt = \log \left(\dfrac{2 \pi}{e^2}\right)$$
where $\{t\}$ is the fractional part of $t$.
I obtained a circuitous proof for the above integral. I'm curious about other ways to prove the above identity. So I thought I will post here and look at others suggestion and answers. 
I am particularly interested in different ways to go about proving the above.
I'll hold off from posting my proof for sometime to see what all different proofs I get for this.

REPLY [2 votes]: The integral on $[1,N+1]$ is (see @Rahul's first comment)
$$
I_N=\sum_{n=1}^N\big(2+2\log n+(2n-1)\log n-(2n+1)\log(n+1)\big),
$$
that is,
$$
I_N=2N+2\log(N!)-(2N+1)\log(N+1).
$$
Thanks to Stirling's approximation, $2\log(N!)=(2N+1)\log N-2N+\log(2\pi)+o(1)$. After some simplifications, this leads to
$$
I_N=\log(2\pi)-(2N+1)\log(1+1/N)+o(1)=\log(2\pi)-2+o(1).
$$