TITLE: What is the reason for naming a function odd or even
QUESTION [5 upvotes]: We say that a function is called odd if $$f(-x)=-f(x)\\     (1)$$ and a function is called even if $$f(-x)=f(x)\\\\\\ (2)$$ But why do we call them odd and even. It feels a very peculiar choice of naming. After a bit of work what I saw is this: 
$$
\begin{array}{ | m{1cm} | m{1cm}| m{5em}| } 
\hline
f(x) & g(x) & f(g(x)) \{\text{even/odd}\} \\ 
\hline
even & even & even \\ \hline
\hline
even & odd & even \\ \hline
\hline
odd & even & even \\ \hline
\hline
odd & odd & odd \\ 
\hline
\end{array}
$$
Now if we think functions as numbers in $\Bbb{N}$then whatever happens in the above table hold true if we think of composition of functions as multiplication of numbers in $\Bbb{N}$. But it does not feel right to take multiplication as the same as composition of functions. So is there any other reason why we have named functions which goes according to the properties $(1)$ and $(2)$ as odd and even respectively.
Note: I have written a table which does not seem to process. So if someone can kindly edit the question and fix the table it would be very good. Thankyou

REPLY [2 votes]: Does that really seem peculiar to you?  Why do we call numbers divisible by two "even" and those that aren't "odd".  "even" means....  well, "balanced", level, symmetric etc. An even number splits perfectly in half so "even" makes sense.  Likewise if f(-x) = f(x) it's graph is a perfect mirror image: reflective and the same in either direction... i.e. "even".  Odd also means self-reflective but off kilter.  An odd number splits in to halves with a center unbalanced core.  An odd function f(-x) = -f(x) rotates and fits onto itself but isn't reflexive.  The negativity influences it.  It's an odd weighting factor.
But the best mnemonic and probably the origin of the term is the function $f(x) = x^n$ which is even or odd precisely when $n$ is odd or even.
... or it may have something to do with transformations.  If you rotate something by $k\pi$ radians.  If $k$ is odd that an odd rotation and the function is upside down.  If $k$ is even those are even rotation and the function is back to its cheery rightside up.