TITLE: How to show that the circle group T is isomorphic to $\mathbb R/ \mathbb Z$
QUESTION [7 upvotes]: the circle group is the multiplicative group of all complex numbers of absolute value 1. How can i show that this group is isomorphic with $\mathbb R/ \mathbb Z$. Any hints for the right map is great.

REPLY [7 votes]: The map $\phi\colon\Bbb R\to T$ given by $\phi(t)=e^{2\pi it}$ is a group morphism. Hence we can apply first isomorphism theorem.