TITLE: Is there an example for $\|f_n-f\|_p\rightarrow 0$, but $\|f_n\|_p\nrightarrow \|f\|_p$, $0<p<1$
QUESTION [6 upvotes]: I know that if $p\geq1$, $\|f_n-f\|_p\rightarrow 0$ implies $\|f_n\|_p\rightarrow \|f\|_p$, since then Minkowski inequality holds for the $L^p$ norm ($p\geq1$). 
Is there an example for $\|f_n-f\|_p\rightarrow 0$, but $\|f_n\|_p\nrightarrow \|f\|_p$, when $0<p<1$ and $\|f_n\|_p, \|f\|_p<\infty$?
Here $\|f\|_p=(\int_\Omega|f(x)|^p \mathrm{d}x)^{1/p}$.
Nathanael Skrepek's anwer reminded me that though the Minkowski inequality does not hold when $p<1$, the Cr inequality still implies the convergence.

REPLY [8 votes]: So I am afraid that this is not possible.
Lets denote $\rho(f) := \|f\|_p^p = \int_\Omega |f|^p \mathrm{d}\mu$. Note that $\rho$ fulfils the triangle inequality (Wikipedia reference). This leads to
\begin{align}\rho(g) &= \rho\big(f+(g-f)\big) \leq \rho(f) + \rho(g-f) \\
\rho(g) - \rho(f) &\leq \rho(g-f)
\end{align}
and furthermore to $|\rho(g) - \rho(f) |\leq \rho(g-f)$.
Endowed with this knowledge lets consider your case:
We know that from $\|f_n-f\|_p \to 0$ follows
\begin{align}
\rho(f_n-g)=\|f_n-f\|_p^p \to 0.
\end{align}
By applying the previous result we receive
\begin{align}
\big|\|f_n\|_p^p-\|f\|_p^p\big|=|\rho(f_n)-\rho(f)| \leq\rho(f_n-g)\to 0.
\end{align}
Now we know that $\|f_n\|_p^p \to \|f\|_p^p$ holds. Since the range of $\rho:f \mapsto \int_\Omega|f|^p\mathrm{d}\mu$ is $[0,+\infty)$ the function $x\mapsto x^{q}$ (for every $q>0$) is well defined and injective on the range of $\rho$. Hence we also can conclude that
\begin{align}
\|f_n\|_p \to \|f\|_p
\end{align}
holds.