TITLE: Are all manifolds in the usual sense also "vector manifolds"?
QUESTION [9 upvotes]: In geometric calculus, there is a concept of a vector manifold where the points are considered vectors in a general geometric algebra (a vector space with vector multiplication) which can then be shown to have the properties of a manifold (tangent spaces etc.). For a more precise definition of a vector manifold, see page 65 of 
http://montgomerycollege.edu/Departments/planet/planet/Numerical_Relativity/bookGA.pdf
For what I believe to be the standard definition of a manifold see page 93 of the same book. This question doesn't seem to be answered inside the above book.
It seems that this approach is simpler than the traditional coordinate approach to manifolds since it is automatically independent of coordinates, except it might be less general. So, my question is: Are all manifolds to be vector manifolds or at least for every usual manifold to be isomorphic to some vector manifold? If not, are there simple additional criteria necessary to add to a manifold in order for it to be isomorphic to a vector manifold?
Note: I'm new to differential geometry, so feel free to correct anything above which may be incorrect. Also, thank you for any ideas/advice/answers you give.

REPLY [5 votes]: To answer your question I will give some context.
Firstly, the concept of Universal Geometric Algebra (UGA). The elements of UGA are called multivectors, among them are the special elements called vectors,
pseudoscalars and scalars. The scalars are said to be identical to the real numbers- complex numbers are unnecessary. UGA is generated from an infinite dimensional vector space. One can generate every finite dimensional Geometric Algebras by the selection of it's pseudoscalar - hence the name UGA.
for precise mathematical details see chapter 1 of "from Clifford Algebras to Geometric Calculus" where the concept was first introduced.
For an up-to-date quick explanation see this tutorial
Secondly, the concept of vector manifold. A set of points (endowed with an algebraic structure) such that at each point
there is a pseudoscalar of definite dimension. The dimension of the pseudoscalar is the dimension of the vector manifold. The algebraic structure imposed on the points is that of the vectors in UGA. By which I mean the points of the vector manifold are vectors in UGA.
The points in the vector manifold are NOT closed under addition and
multiplication by scalars. They do NOT generate a vector space of finite dimension.
A manifold is then defined as a set of points isomorphic to a vector manifold. So in this way the "shape" of the manifold is given by the vector manifold and a manifold is the set of points which have the same "shape" but do not have the algebraic structure imposed on them. If you have a manifold which is locally like $\mathbb R^n$, $n$ is what I was calling the dimension of the pseudoscalar. 
The way in which one constructs a vector manifold is similar to the way one constructs a GA, by the choosing of a psuedoscalar. The difference is that in the vector manifold the pseudoscalar is not constant, it is a function of points on the vector manifold. If the pseudoscalar is differentiable then so is the vector manifold. From this pseudoscalar one can calculate all quantities relevant to differential geometry i.e. the curvature.
See chapter 5 of the same book referred to above for precise mathematical details.
For an up-to-date explanation see chapter 19 of "Guide to Geometric Algebra in Practice". This chapter is available here
The name is appropriate as the points are abstract vectors in UGA, however
it might be unfortunate as some misguidedly believe that vector manifolds are less general. This might be because GA has a metrical interpretation and so concepts such as inner product and pedusoscalar which do have very important metrical interpretations are confused at the abstract level. GA also has a projective interpretation where the inner product and the pseudoscalar are given different interpretations. These can be found in the article which Muphrid provided. (the definition of inner product in GA is the symmetrical part of the geometric product, the product which defines the algebra)