TITLE: Infinite area under curve without using derivatives and integrals
QUESTION [22 upvotes]: I am looking for a function $f$ with the following properties:

$f$ is continuous on $[0,\infty[$
$f(0)=1$
$f(x)\to0$ as $x\to\infty$
$\int_0^{\infty} f(x) \,\mathrm{d}x = \infty$

It is not difficult to find a such a function, for example $f(x) = 1/(x+1)$ would do it. However, I am looking for an example where I can "proof" that the area under the curve (i.e. $\int_0^{\infty} f(x) \,\mathrm{d}x $) goes to infinity for $x \to \infty$ for an audience which doesn't know of how to integrate or differentiate functions. 
So a "visual" proof would be sufficient too.

REPLY [3 votes]: Start with the trapezoid $T_0$ with vertices $(0,0)$, $(1,0)$, $(1,{1\over2})$, $(0,1)$. It has area ${3\over4}$. Shrink $T_0$ vertically by the factor ${1\over2}$ and extend it horizontally by the factor $2$ to obtain $T_1$ (of the same area as $T_0$), and put $T_1$ flush to the right of $T_0$. Then shrink $T_1$ vertically by the factor ${1\over2}$ and extend it horizontally by the factor $2$ to obtain $T_2$, and put $T_2$ flush to the right of $T_1$, and so on ad infinitum.