TITLE: Precise definition of Dihedral Group
QUESTION [5 upvotes]: I am studying " Abstract Algebra " written by dummit/foote.
In page 23, This book defines the concept of dihedral group as follows:
For each n = 3, 4, 5, etc... , 
The set of symmetries of a regular n-gon, where a symmetry is any rigid motion of the n-gon which can be effected by taking a copy back on the original n-gon so it exaclty covers it.
I can understand what it means but I have some curious about this definition
because this definition is not rigorous for me.
What is the definition of rigid motion? what is copy back?
Can we admit this kind of vague terminology in math? 
I tried to find other book which describing the concept symmetry.
In the book " A first course in Abstract Algebra, this book defines a symmetry of geometrical figure as a rearrangement of the figure preserving the arrangement of its sides and vertices as well as its distance and angles.
I thought that this definition is also depending on our intuition... and not rigourous if we compare this with set theory, real analysis, or other mathematical definition...
So, In summary...
Q1. I understood that symmetry is a transformation which preserves shape, angle, distances... in intuitive meaning Did I understand well?
Q2. If I understood well, what is a precise and rigorous definition of symmetry? as we did in set theory, real analysis, etc...
Q3. Can we deal geometry by using a precise and rigorous method only using axiom, set, logic ??

REPLY [2 votes]: To begin with, you haven't accurately quoted the passage in D & F, page 23. They write "a symmetry is any rigid motion of the $n$-gon which can be effected by taking a copy of the $n$-gon, moving this copy in any fashion in 3-space and placing the copy back on the original $n$-gon so it exactly covers [the original copy]."
This is intuitive to you because you can imagine actually doing it physically with two paper models of the $n$-gon, one taped to your table and one free to move in space.  
It also has an absolutely precise mathematical meaning.  You are to consider "rigid motions" of all of 3-space which carry the $n$-gon to itself, i.e. rigid motions $T : \mathbb R^3 \to \mathbb R^3$ such that $T(P) = P$, where $P$ denotes the $n$-gon.  
And what is a rigid motion of $\mathbb R^3$?  It is an orientation preserving isometry, equivalently a map $x \mapsto A x + b$, where $A$ is a rotation of 3-space.  Moreover, a rotation of 3-space is a linear isometry with determinant equal to 1.  
Now one can show that if $T$ is a rigid motion of $\mathbb R^3$ taking $P$ to $P$, then $T$ must take vertices of $P$ to vertices and must take the center of mass of $P$ to itself.  Without loss of generality, put the center of mass at the origin.  Then $T$ must fix the origin and therefore $T$ is a rotation of 3-space.
Thus one ends up with the following:

A symmetry of the $n$-gon $P$ is a rotation of 3-space that takes $P$ onto $P$.

Alternatively,  one could define symmetries of $P$ just to be isometries of $P$, regarded as a metric subspace of Euclidean 3-space.  But one can show that each such symmetry extends to a rigid motion of 3-space, so this does not result in a more general notion of symmetry.
Reference: this book, sections 1.4, 2.3, 11.1.