TITLE: How to solve $\left(\frac3{p-3}-1\right)\left(2+\frac4{p-2}\right)=0$?
QUESTION [5 upvotes]: I'm currently preparing myself for uni and thus learning on my own. This equation is killing me as the book doesn't explain how to solve it.
$$\left(\frac3{p-3}-1\right)\left(2+\frac4{p-2}\right)=0$$

REPLY [5 votes]: By Null -Factor law,
If xy = 0 ,
Then, either x = 0 or y = 0.
Hence, applying this property in this given equation :
We get ,
Equate both terms on Left side factor  and Right side factor of left hand side equation  to $0$
$$p-3 = \frac 31  \implies  p = 6$$
Or :
$$p-2= -2 \implies  p = 0$$ 
So, either $p = 0$ or $p = 6$

REPLY [2 votes]: By the null factor law, if $xy=0$ then $x=0$ or $y=0$. Apply this to your equation and you'll get two answers.