TITLE: Another basic Ordinal arithmetic question: $\omega \cdot (\omega+1)=?$
QUESTION [5 upvotes]: I am getting confused about ordinal arithmetic 
I am trying to figure out what $\omega \cdot (\omega+1)$ is. 
The fact that the distributive law applies from the left side makes me think that the answer is $\omega^2 + \omega$. However applying the supremum definition of multiplication I am getting a different answer. The supremum method is giving me: $$\omega \cdot (\omega+1) = \sup \{\omega \cdot n \ | \ n \in \omega+1 \} = \omega^2 $$
Since $\omega^2 \geq \omega \cdot n, \forall n < \omega + 1$.
Which way is correct and why is the other method wrong here?

REPLY [4 votes]: The second method is wrong, because the definition of multiply that you used in second method is right only when the second ordinal is a limit ordinal, so if the second ordinal is something like $\omega+1$ the definition of multiply is the distributive law :$a(b+1) = ab+a$