TITLE: Are there any continuous functions from the real line onto the complex plane?
QUESTION [8 upvotes]: Is there any 

measurable
continuous
differentiable
analytic

surjective function $f:\mathbb{R}\to\mathbb{C}$?

REPLY [6 votes]: I recently learned the following related result, which I think deserves some publicity: Say that $f:\mathbb R\to\mathbb R^2$ is a Peano function iff it is surjective. As pointed out in the other answer, and the links in the comments, no Peano function is everywhere differentiable. 
In 1984, Morayne proved that the continuum hypothesis is equivalent to the existence of a Peano function $f(x) = (f_1(x),f_2(x))$ such that, for every $x\in\mathbb R$, at least one of $f_1'(x)$ and $f_2'(x)$ exists. The reference is 

Michał Morayne. On differentiability of Peano type functions, Colloq. Math. 48 (2) (1984), 261–264. MR0758535 (86i:26008).

In the same reference, he proves a related negative result, showing that such functions are necessarily "pathological": Suppose that $f_1,f_2:\mathbb R\to \mathbb R$, let $f=(f_1,f_2)$, and assume that $f_1$ is a Lebesgue measurable function, and $f(\mathbb R)$ is a Lebesgue measurable subset of the plane. If for each $x\in\mathbb R$ at least one of the derivatives $f_1'(x), f_2'(x)$ exists, then $f(\mathbb R)$ has measure zero, so in particular, it cannot be the whole plane.
For an additional set theoretic connection, in recent work, Asger Törnquist and William Weiss have shown that the existence of a Peano function $f(x) = (f_1(x),f_2(x))$ such that, for every $x\in\mathbb R$, at least one of $f_1'(x)$ and $f_2'(x)$ exists, and the functions $f_1,f_2$ are $\Sigma^1_2$, is equivalent to the assertion that $\mathbb R$ is contained in $L$, Gödel's constructible universe.