TITLE: Matrix determinant effect
QUESTION [7 upvotes]: Determinant of the matrix $$A= \begin{bmatrix}a&b&c\\d&e&f\\g&h&i\end{bmatrix}$$
is $$\det A=4.$$ So what is the determinant of \begin{bmatrix}3a&3b&3c\\-d&-e&-f\\g-a&h-b&i-c\end{bmatrix}
I found that the row operations that were done were $3R1, -1.R2,$ and the last one doesn't matter.
So is the determinant $3\times 4\times(-1)= -12$
or we have to do the inverse $4\times 1/3 \times 1/(-1)?$

REPLY [5 votes]: Sometimes you can't tell if matrix $B$ can be generated from matrix $B$ or not.  In such a case, one may expand each determinant and compare the result of each. However, this approach requires careful attention to signs!
Let $X$ be the determinant of the first matrix and $Y$ be the determinant of the 2nd matrix, then we have:
$ X = a(ei - fh) - b(di - fg) + c(dh - eg) $ 
$ X = aei - afh - bdi + bfg + cdh - ceg $
$ Y = 3afh - 3eai + 3ecg + 3bdi - 3bfg - 3cdh $
$ \frac{Y}{-3} = -afh + eai -ecg -bdi + bfg + cdh  $
You could re-arrange the terms of any of the equations to see that:
$X=\frac{Y}{-3}$
Since X=4, 
$Y=-12$