TITLE: How many ways can we define prime number?
QUESTION [6 upvotes]: So the other day I was in an interview for a PhD program, one of the professors asked me to give the definition of a prime number. So I gave him the following usual definition- 

Any positive number $p>1$ is called a prime number if the only divisors of $p$ are $1$ and $p$ itself.

Then he asked me what are the other definitions of a prime number? To which I had no answer as I don't know any other definition. Then he said the following- 

A natural number $n > 1$ is a prime number if and only if $(n-1)!=-1 (\text{mod} ~n).$ 

Which is basically the statement of Wilson's theorem.
My question is, can we use these kind of results//theorems as definitions of prime numbers? 
If I say, "for any natural number $n>1$, if $\phi(n)=n-1,$ then $n$ is a prime, where $\phi$ is Euler's Totient function." would also qualifies to be a definition of prime number? 
If so what are the other definitions of prime numbers? 
Thanks for any valuable input. 
Edit: So from the comments I got several examples, thanks for that, I got the idea. So now I want an answer to the question, can we use these kind of results//theorems as definitions of prime numbers?

REPLY [2 votes]: I'm going to elaborate on the comment that a number $p$ is prime if $p \mid ab$ means either $p \mid a$ or $p \mid b$.
Consider for example $p = 14$. That's not actually prime, but indulge me for a minute. Check that $14 \mid 112$ and $112 = 7 \times 16$. However, $14 \nmid 7$ and $14 \nmid 16$ either. Therefore $14$ is not prime. However, $2$ and $7$ are prime, since for any choice of $a$ and $b$ such that $ab = 112$, you will see that either $a$ or $b$, maybe both, are divisible by $2$ and/or by $7$.
The definition you gave is equivalent to saying if $ab = p$, then either $a$ or $b$ is a unit (like $-1$). And that definition is fine until you venture out to domains of numbers other than $\mathbb{Z}$. For example, are the numbers $3 \pm 2 \sqrt{10}$ prime? Yes, they are. How about $\sqrt{10}$? It satisfies the $ab = p$ definition but not the $p \mid ab$ definition.