TITLE: Probability of drawing two cards such that one is a spade and other one is a heart.
QUESTION [5 upvotes]: I got the answer of this question via two methods

$(13÷52)*(13÷51)*2............(i)$

And the second is 

$(13C1*13C1)÷(52C2).........(ii)$

I know that both will give same numerical correct answer, but I'm confused from the fact that in first equation we multiplied by $2$ which means that either spade or heart can be drawn first so why can't we multiply second equation using same logic? Please help if I'm missing something really important. Thanks in advance.

REPLY [2 votes]: Let me suggest another way to solve the problem that might help you think about it.  You have $26$ choices out of $52$ of a first card that keeps you "alive."  After choosing that first card, you have $13$ choices out of $51$ of a second card that keeps you alive.