TITLE: A 'collection' of elements which does not form a set
QUESTION [5 upvotes]: Reading Halmos' 'Naive Set Theory', I learn that these ZFC set axiom are used to recognise set that are set intuitively.
And the axiom of power, stated as 'For each set $X$, there exists a collection (set) of sets that contains among its elements all the subsets (again a set) of the given set.'
I am actually curious of whether there can be a 'collection' (not a set, it is a 'collection' of elements I have implicitly) 'inside' $X$ (not a subset, since is not a set).
This question may seem strange, one of the motivation is that in the power set $P(X)$, any element are subset of $X$ which is itself a set, I wonder if some 'collection' are already omitted. Another motivation is that any set to be chosen must be 'specific', that is, constucted under a sentence with set-builder notations (under axiom of specification).
I would like to formulate the statement and proof as follows, but fail even to state it.

Statement: Given a 'collection' of element (all $\in X$), it must form a set. (Prove or dispove)

Proof: ...
Problem I find in the statement: I already have in mind a 'collection' of objects, this seems like I can use axiom of specification to construct it as subset. But I really don't know what this set could be, if I really 'know' them, I am actually trying to index them (reducing unknown to known), this is already assuming they form a set (by considering range, which form a set by specification)
The whole problem lies on the definition of 'collection' (not a set). But in ZFC in the book, every objects to study are sets, so it does not really make sense.
Maybe another better way to formulate is if in a larger 'model', can there be defined another other object that is 'inside' $X$ (every element $\in X$)  but not a set.
Sorry for being not specific, I will edit it later.

REPLY [6 votes]: Yes, this is possible. One of the ways to see this is the idea of forcing as a tool for adding new sets to the universe.
The first example is adding a new set of integers. As the new set is made only of integers, it is "a collection of integers" but it is not a set in the model. It is not a class either, though. It just exists in a larger universe.
The problem here is that collections might hold information that contradicts with the rest of the axioms of ZF(C). For example, if $M$ is a countable model of ZFC, then there is a bijection between $M$ and the natural numbers (of $M$), which means that there is a collection of integers which codes the whole model.
If we add that collection as a set, then $M$ would be able to recognise itself as a set. Or at least it should. But it really can't. So you will have to violate the axioms of ZFC if you add that as a set.
Finally, it is important to point out that when we have this sort of situation where there is a collection which is a sub-collection of a set, but not a set, then this collection is not definable, and there is no way for the model you're working in to recognise it. In particular, it is not a class either. We are only able to talk about these collections from outside the model.

REPLY [2 votes]: You can define, for example, a "class", which is formally nothing more than a predicate, but which we think of "the things which satisfy that predicate". The axiom schema of comprehension tells us that certain classes are in fact sets (namely, if the class is defined as a subclass of a set).
There is a class of all sets: one appropriate predicate is simply "true".
The empty set is a class: for example, a predicate would be "false". There is a class of all finite sets: such a predicate would be "there is a bijection from $X$ to some finite ordinal".