TITLE: Associated Primes of Tensor Product
QUESTION [6 upvotes]: Let $R$ be a Noetherian ring, and let $M$ and $N$ be finitely generated $R$ module. Do we know any formulas for $\operatorname{Ass}(M\otimes_R N)$ in terms of $\operatorname{Ass}(M)$, $\operatorname{Ass}(N)$ or in terms of $\operatorname{Supp}(M)$ or $\operatorname{Supp}(N)$?
Recall that we have such a formula for the support, i.e., $\operatorname{Supp}(M\otimes_R N)=\operatorname{Supp}M\cap \operatorname{Supp}N$. We also have a formula for $\operatorname{Ass}(\operatorname{Hom}(M,N))$.
I have not seen any formula for Ass of tensor products, it would be nice to have such a formula in at least a few special cases.

REPLY [4 votes]: The following is THM 23.2 in Matsumura's "Commutative Ring Theory":
Let $\phi:A \rightarrow B$ be a homomorphism of Noetherian rings, and let $E$ be an $A$-module and $G$ be a $B$-module.  Suppose $G$ is flat over $A$; then:
(i) If $\mathfrak{p} \in \text{Spec}(A)$ and $ G/\mathfrak{p}G \ne 0$, then, letting $\phi^a: \text{Spec}(B) \rightarrow \text{Spec}(A)$ be the induced map (this is Matsumura's notation) we have $\phi^a(\text{Ass}_B(G/\mathfrak{p}G))=\text{Ass}_A(G/\mathfrak{p}G)=\{\mathfrak{p}$}
(ii) $\text{Ass}_B(E \otimes_A G) = \bigcup_{\mathfrak{p} \in \text{Ass}_A(E)}\text{Ass}_B(G/\mathfrak{p}G)$
So, this answers the question in the case where $M$ is a flat $R$-module; take $A=R=B$, $E=N$, and $G=M$, and apply (ii).
So this isn't very interesting when $R$ is local, for instance...but it is the best I can do.