TITLE: Advantage of the more general notion of "neighborhoods" in topology
QUESTION [21 upvotes]: The notion of "open sets" is a fundamental concept in topology. I have been puzzled by (the use of) another slightly more general but closely related one: neighborhoods. Given a topological space $(X,\tau)$, and a point $p\in X$, a neighbourhood of $p$ is a subset $V$ of $X$ that includes an open set $U$ containing $p$, 
$$
p\in U\subset V.
$$
On the other hand, given a "neighborhood system" on a set $X$, one can define a topology that is consistent with the notion of "neighborhoods". 
This Wikipedia article makes a remark that "Some mathematicians require that neighbourhoods be open". (For instance, in Munkres's Topology (c.f. page 96), the statement "$U$ is an open set containing $x$" is considered as equivalent to "$U$ is a neighborhood of $x$".)
Question: What is the advantage of the more general notion of "neighborhoods" (that is not required to be open) in practice? Is it simply a matter of taste or does it make significant simplifications in some statement of theorems, proofs or definitions?

Notes: Please note that this is question is not asking the definitions of "neighborhoods" and "open sets" as the suggested linked question did.

REPLY [18 votes]: It makes for easier formulation of some theorems or definitions: a space can be called locally compact if it has a (base of) compact neighbourhoods, or locally connected if it has a local base of connected neighbourhoods (regardless of openness). 
The formulation of local continuity is also easy: $f$ is continuous at $x$ if $f^{-1}[N]$ is a neighbourhood of $x$ for every neighbourhood $N$ of $f(x)$.
$X$ is regular iff every point has a local base of closed neighbourhoods.
A filter $\mathcal{F}$ converges to $x$ iff it contains all neighbourhoods of $x$.