TITLE: Which logic is stronger? SOL or $\frak{L}_{\infty,\infty}$?
QUESTION [8 upvotes]: Both second-order logic($\mathsf{SOL}$) and infinitary first-order logic $\frak{L}_{\infty,\infty}$ are proper extensions of first-order logic($\mathsf{FOL}$), that is, are extensions of a $\mathsf{FOL}$ and also strictly stronger than it in expressive power. It is natural to ask, are they comparable? If so, which one is more powerful?

REPLY [6 votes]: While Model-theoretic logics is indeed a wonderful source, for this particular question it's overkill. The logics $\mathfrak{L}_{\infty,\infty}$ and $SOL$ are incomparable in a precise sense.

One direction is easy. $\mathfrak{L}_{\infty,\infty}$ pins down every structure up to isomorphism: if $\mathcal{A}$ has cardinality $\kappa$ then there is an $\mathfrak{L}_{\kappa^+,\kappa^+}$-sentence $\varphi_\mathcal{A}$ whose models are exactly those structures isomorphic to $\mathcal{A}$. 

Note that in the case $\kappa=\omega$ we have a serious improvement in Scott's isomorphism theorem, which says that $\mathfrak{L}_{\omega_1,\omega}$ (which is vastly better-behaved than $\mathfrak{L}_{\omega_1,\omega_1}$) is enough. That's not true in general beyond $\omega$, though.

By contrast, $SOL$ doesn't do this for the simple fact that it's too small - although it's quite difficult to find a structure SOL can't pin down, we know there must be one (indeed, there has to be one of cardinality $\le 2^{\aleph_0}$).
More generally, $\mathfrak{L}_{\infty,\infty}$ is too large to be a sublogic of any set-sized logic.

It's also the case that $SOL$ is not a sublogic of $\mathfrak{L}_{\infty,\infty}$, although this takes slightly more thought.
The key is:

If $\varphi$ is an $\mathfrak{L}_{\infty,\infty}$-sentence in the empty language, then there is a $\kappa$ such that either $\varphi$ holds of every structure of cardinality $>\kappa$ or $\varphi$ fails of every structure of cardinality $>\kappa$.

This is a good exercise, and in fact we can just take $\kappa=\vert\varphi\vert+\aleph_0$.
By contrast, this is clearly false for $SOL$. For example, there is an $SOL$-sentence in the empty language which is true in exactly those structures whose cardinality is an infinite successor cardinal: "The domain is infinite and there is some subset $A$ of the domain not in bijection with the whole such that every subset of the domain containing $A$ is either in bijection with $A$ or in bijection with the whole domain."

That said, while neither logic contains the other there are definitely comparisons we can draw. On the whole I'd say that $SOL$ captures much more set theory than $\mathfrak{L}_{\infty,\infty}$, and so in that sense is arguably more powerful (and less well-behaved); on the other hand, the logical equivalence relation for $\mathfrak{L}_{\infty,\infty}$ is finer than that for $SOL$ (it's just $\cong$ after all), so when we focus on individual structures as opposed to classes of structures or background set-theoretic facts $\mathfrak{L}_{\infty,\infty}$ thoroughly dominates.