TITLE: Does the categorical notion of a coequalizer coincide with the usual quotient objects considered in algebra?
QUESTION [6 upvotes]: I heard that the category-theoretic formulation of "quotient object" is that of a coequalizer. Instead of taking the quotient of, say, a group $G$ by some normal subgroup, one takes the quotient (really, the coequalizer) by some diagram of the form $H\rightrightarrows G$ consisting of two arrows from some group $H$ to $G$.
I wonder: Can each quotient $G/N$ of $G$ by some normal subgroup $N$ be written as the coequalizer of some diagram $H\rightrightarrows G$? What about the converse: Can each coequalizer be written as the quotient by some normal subgroup?
Of course, I'm not only interested in groups, but I also want to know whether the same things are true for rings/ideals, modules/submodules, and so on.

REPLY [8 votes]: Yes. In a fairly general class of categories, we can define an internal equivalence relation or congruence on an object $X$ to be a subobject $R \subseteq X \times X$ satisfying the axioms of an equivalence relation, suitably generalized so that they can be stated categorically (see the link for details). A congruence, being a subobject of $X \times X$, is equipped with a pair of maps to $X$, and the quotient by a congruence is the coequalizer of this pair of maps.
For groups you can check that every congruence on a group $G$ has the form
$$\{ (g, h) \in G \times G : g^{-1} h \in N \}$$
for a unique normal subgroup $N$. If we write the congruence as an equivalence relation $\sim$ on $G$, then $N = \{ n \in G : n \sim e \}$. So talking about congruences is equivalent to talking about normal subgroups, and furthermore the quotient by the congruence (the coequalizer above) associated to a normal subgroup is the quotient in the usual sense.
The point of writing things this way instead of in terms of cokernels is that this recipe generalizes to settings other than groups. For example, for rings you can check that every congruence on a ring $R$ has the form
$$\{ (r, s) \in R \times R : r - s \in I \}$$
for a unique two-sided ideal $I$, and again quotienting by this ideal corresponds to taking the coequalizer. For more general objects such as monoids and semirings it's not possible to do this kind of reduction and we really just need to work with congruences.