TITLE: Why does the discriminant of a cubic polynomial being less than $0$ indicate complex roots?
QUESTION [22 upvotes]: The discriminant $\Delta = 18abcd - 4b^3d + b^2 c^2 - 4ac^3 - 27a^2d^2$ of the cubic polynomial $ax^3 + bx^2 + cx+ d$ indicates not only if there are repeated roots when $\Delta$ vanishes, but also that there are three distinct, real roots if $\Delta > 0$, and that there is one real root and two complex roots (complex conjugates) if $\Delta < 0$.
Why does $\Delta < 0$ indicate complex roots? I understand that because of the way that the discriminant is defined, it indicates that there is a repeated root if it vanishes, but why does $\Delta$ greater than $0$ or less than $0$ have special meaning, too?

REPLY [7 votes]: These implications are reached by considering the three, different cases for the roots $\{ r_1, r_2, r_3 \}$ of the polynomial: repeated root, all distinct real roots, or two complex roots and one real root.
When one of the roots is repeated, say $r_1$ and $r_2$, then it is clear that the discriminant is $0$ because the $r_1 - r_2$ term of the product is $0$.
When one root is a complex number $\rho = x+ yi$, then by the complex conjugate root theorem, $\overline{\rho} = x - yi$ is also a root. By the same theorem, the remaining third root must be real. Evaluating the product in the discriminant for this case,
$$
\begin{align*}
(\rho - \overline{\rho})^2 (\rho - r_3)^2 (\overline{\rho} - r_3)^2 
&= (2yi)^2 (x + yi - r^3)^2  (x - yi - r^3)^2 
\\ &= -4y^2 [((x - r_3) + yi) ((x - r_3) - yi) ]^2 
\\ &= -4y^2 ((x - r_3)^2 + y^2)^2 
\end{align*}
$$
which is less than or equal to $0$.
Finally, when all roots are real, the product is clearly positive.
Putting it all together, $\Delta$:

less than $0$ implies that one root is complex;
equal to $0$ implies that one root is repeated;
greater than $0$ implies that all roots are distinct and real.