TITLE: Solve $4^{9x-4} = 3^{9x-4}$
QUESTION [13 upvotes]: I am having some trouble trying to solve 
$$4^{9x-4} = 3^{9x-4}$$
I tried to make each the same base but then I'm becoming confused as to what to do next.
These are the steps I took:
$$\begin{align}
4^{9x-4} &= 3^{9x-4} \\
\log_4(4^{9x-4}) &= \log_4(3^{9x-4}) \\
\end{align}$$
Where do I go from there?
Thanks!

REPLY [3 votes]: For any $A^n = B^n$ where $A \ne B$, $n = 0$
So:
$$9x - 4 = 0$$
$$x = 4/9$$