TITLE: On the definition of a geodesic in a metric space
QUESTION [10 upvotes]: I am interested in the definition of geodesics in metric spaces. A definition which seems reasonable to me is that a geodesic should locally be a distance minimizer. 
Wikipedia (http://en.wikipedia.org/wiki/Geodesic#Metric_geometry) states that this naturally leads one to define a geodesic as a curve $\gamma: I \to M$, with $I\subset \mathbb{R}$ an interval and $M$ a metric space, such that for any $t \in I$ there is a neighbourhood $J$ of $t$ so that for any $t_1, t_2 \in J$ we have
$$
d(\gamma(t_1), \gamma(t_2)) = v |t_1 -t_2|,
$$
where $v \geq 0$ is any constant.
Am I missing something obvious? Why is it that a curve satisfying this formula is locally minimizing the distance between its points? I have no reason to think this is false, but also no intuition as to why this is true.
Thank you in advance!

REPLY [3 votes]: It's worth noting that the constant $v$ necessarily depends on the points $x,y\in M$ that you wish to connect with a geodesic, since the infimum of the lengths of (rectifiable) curves from $x$ to $y$ is not necessarily the same as $d(x,y)$, and may vary from $d(x,y)$ by a different factor for different choices of $x$ and $y$. With the two points chosen, I think Wikipedia's definition is pretty intuitive: a geodesic is a path that is (proportional to) an isometry of $I$ "near" each point in $I$.