TITLE: Smallest topology containing a family of other topologies on a set $X$
QUESTION [10 upvotes]: Let $T_a$ be a family of topologies on a set $X$. What is the smallest topology containing all the $T_a$? Obviously, the smallest it could be is the union of all the $T_a$, but that's not always a topology. So is it just the topology generated by the subbasis $\bigcup T_a$? I feel like this is too simple of an answer, since the question is phrased asking to prove that there is a unique smallest topology containing all the $T_a$.
(I'm working through Munkres' Topology on my own.)

REPLY [6 votes]: As Daniel wrote it is the topology that has $\bigcup T_a$ as a subbasis. So it is the set of all unions of finite intersections of sets in $\bigcup T_a$. Another way to describe it is as the intersection of all topologies on $X$ containing $\bigcup T_a$ (there is at least one, namely the power set $\mathcal P(X)$ ).  However, we can make use of the knowledge that each $T_a$ is a topology, because this requires us to only intersect sets from different $T_a$'s. For example, if you have $T_1$ and $T_2$, then the smallest topology containing them is the set of unions of sets of the form $U_1\cap U_2$, where $U_1\in T_1$ and $U_2\in T_2$. In particular, if $T$ is any topology and $T_2$ is the topology $\{\emptyset, X, A\}$, for any subset $A$ in $X$, then the smallest topology is called $T(A)$ and it can be expressed as
$$T(A)=\{U\cup(V\cap A)\mid U\in T, V\in T\}$$