TITLE: Rational singularities for normal varieties
QUESTION [7 upvotes]: On page 17 of this paper
there is the following claim.

For $f: Y \rightarrow X$ a proper birational map with $Y$ smooth (i.e. a desingularization of $X$) and $X$ is a normal variety,  $R^i f_* \mathcal{O}_Y = 0$ for $i>0$ is equivalent to $Rf_* \mathcal{O}_Y \simeq \mathcal{O}_X$ in the derived category.

I can't see why this is true.  Does anyone know why, or know a good reference where I could find the answer?
Bonus question: is it true that for $f: Y \rightarrow X$ a proper birational map with $Y$ smooth, that $X$ is normal if and only if $f_* \mathcal{O}_Y = \mathcal{O}_X$? (nonderived pushforward)

REPLY [3 votes]: I found an answer.  Higher derived structure is not relevant.  Let $f: Y \rightarrow X$ be a proper birational resolution of singularities, with $X$ normal.  This problem is local on the base so we may assume $X$ is affine.
Since $f$ is birational, $\Gamma(Y, \mathcal{O}_Y) \subset \text{Frac}(\mathcal{O}_X)$.
Since $f$ is proper, pushforward of coherent sheaf is coherent, so $\Gamma(Y, \mathcal{O}_Y)$ is a finite $\mathcal{O}_X$-module.
Since $X$ is normal, a finite $\mathcal{O}_X$-module in its field of fractions is itself.  (Converse is also true).