TITLE: Possible method to prove infinite twin prime conjecture
QUESTION [9 upvotes]: I have an idea looking more and more promising that may lead to proving the infinite twin prime conjecture. My idea would set up a correspondence between primes and twin prime pairs. Since primes have been proven infinite, twin primes would be shown infinite as well. Here it is:
For every prime $p>7$ there exists at least one unique twin prime pair $(p_t,p_t+2)$ created using only primes less than $p$ as follows: 
$$(p_t,p_t+2)=(3\times5\times P_p\times p-4,\ \ 3\times 5\times p\times P_p-2)$$
or
$$(p_t,p_t+2)=(3\times5\times P_p\times p+2,\ \ 3\times5\times p\times P_p+4)$$
where $P_p$ is some product of individual primes ($p_n$) and their powers (although recent developments indicate powers may be unnecessary!) such that each fits the following condition: 
$$5<p_n<p$$
Here's a few examples:
$(3\times5\times43-4,\ \ 3\times5\times43-2)=(641,643)$
$(3\times5\times7^2\times11\times47+2,\ \ 3\times5\times7^2\times11\times47+4)=(379997,379999)$
My request is for one of the following:

Someone to refine our program for a brute force testing method trying to find a counter-example to disprove my conjecture. Here's the code:

Original Wolfram Notebook 
NEW AND IMPROVED Wolfram Notebook

Someone to develop a proof of my conjecture; perhaps something related to the fact that the multitude of combinations/permutations etc. of primes ($5<p_p<p$) and their powers requires that there be at least one twin prime pair created. Perhaps a proof by contradiction? I.e. $p$ exists such that no twin prime is created is proven absurd, thus each $p$ maps to a unique twin prime, and as primes are infinite, so are twin primes? Need some help here! Maybe someone with rep to spare set a bounty? 

EDIT (2/15/16)
Thanks to @dbanet, I now have code needing some refinements. Still, what's astonishing is that we've checked the first $10,000$ primes and each has its own unique twin prime pair... and it didn't even require powers of primes; everything is to the 1st power! This fact alone should lend high credence to the conjecture that each prime may be mapped to (at least one) unique twin prime pair. I'm considering perhaps removing powers of primes from the original question. 
Here's the list up to 109 for verification. You can check each by adding $4$ or subtracting $2$ from the first in the pair and looking at the prime factors. All will include $3$, $5$ , $p$, and primes between $5$ and $p$ all to the $1$st power (prime#, prime, twin prime):

4, 7, {101},{103}
5, 11, {1151},{1153}
6, 13, {191},{193}
7, 17, {4337},{4339}
8, 19, {281},{283}
9, 23, {347},{349}
10, 29, {431},{433}
11, 31, {461},{463}
12, 37, {17207},{17209}
13, 41, {617},{619}
14, 43, {641},{643}
15, 47, {1225997},{1225999}
16, 53, {37361},{37363}
17, 59, {881},{883}
18, 61, {55817},{55819}
19, 67, {3616997},{3616999}
20, 71, {1061},{1063}
21, 73, {1091},{1093}
22, 79, {6141857},{6141859}
23, 83, {5922461},{5922463}
24, 89, {546625097},{546625099}
25, 97, {1451},{1453}
26, 101, {134837},{134839}
27, 103, {13888001},{13888003}
28, 107, {1607},{1609}
29, 109, {16969661},{16969663}
EDIT (2/15/16)PM
Got a new list of twin primes because of https://mathematica.stackexchange.com/questions/107417/memory-limit-hit-optimize-code-for-finding-twin-primes .
Here's the list of primes $2000-10000$ with the corresponding twin prime pairs!
https://dl.dropboxusercontent.com/u/76769933/8000%20twin%20primes.txt
And just for kicks here's the $100,000,000$th prime with the first found (probably not only) twin prime unique to it: $2038074743$ -- $(126984732620985857058143952617,$ $126984732620985857058143952619)$

REPLY [2 votes]: I don't see at all how the idea in this question would get us any closer to proving the twin prime conjecture. I know that sometimes, ideas that appear to get you no closer actually do get you closer. For example, Bertrand's postulate states that there is no prime number that is more than double the previous prime number. There's actually a proof of Bertrand's postulate that's not very long, and it's gotten by combining many results each of which appears to not be at all useful for proving Bertrand's postulate. The proof can be found in the Wikipedia article Proof of Bertrand's postulate.
I have another idea. The notion of $Z_n$ has been invented by the mathematical community. In $Z_n$, the only numbers are the integers from 0 to $n - 1$. Addition in $Z_n$ is also defined as follows. To add two numbers in $Z_n$, you take their sum using regular addition then subtract $n$ if the result is greater than or equal to $n$.
In $Z_{2 \times 3 \times 5}$, in otherwords $Z_{30}$, you have 3 pairs of number 2 apart that are coprime to 30. Now, let's see what happens when we take all the pairs of numbers 2 apart that are coprime to 210 in $Z_{210}$. Take all the pairs that are 1 more and 1 less than a multiple of 30. Exactly one of those pairs has a multiple of 7 in the higher number and exactly one of them has a multiple of 7 in the lower number. Furthermore, the one with a multiple of 7 in the higher number is necessarily distinct from the one with a multiple of 7 in the lower number. A similar thing is true for all pairs that are 11 more and 13 more than a multiple of 30. The same goes for all pairs that are 17 more and 19 more than a multiple of 30. This proves that exactly $3 \times 5$ such pairs exist in $Z_{210}$. Similarly, it can be proven that exactly $3 \times 5 \times 9$ such pairs exist in $Z_{2,310}$ and so on. The problem is 169 is less than 2,310 so pairs of number 2 apart that are coprime to 2,310 and less than 2,310 are not necessarily twin primes. Maybe some day, we will be able to find a proof of certain random properties of the distribution of such pairs in $Z_n$ where $n$ is the product of all prime numbers less than a very large prime number $p$ and prove from the random properties that some of those pairs are less than $p^2$ and are therefore twin primes.