TITLE: What is the fewest number of squares required to cover a $11\times13\text{ cm}$ rectangle without overlap?
QUESTION [6 upvotes]: I need help figuring out this math puzzle: I have a $11\times13\text{ cm}$ rectangle and I need help figuring out the least number of squares I need to cover the rectangle without overlap. I'm told the answer should be at most 5. If you can, provide a picture to help me understand.

REPLY [3 votes]: The given rectangle can be divided in to either 3 columns containing 1,2,2 squares or 2 columns containing 4,1 or 3,2 squares. Both possibilities, even using non integer side lengths, won't give 11 x 13. It cannot be done using 5 squares.
The least has to be 6. The one you got.