TITLE: How does the product construction of the Stone-Cech compactification work?
QUESTION [6 upvotes]: Wikipedia's article on the Stone-Cech compactification gives several constructions of it, one which is this:

One attempt to construct the Stone–Čech compactification of $X$ is to take the closure of the image of $X$ in $${\displaystyle \prod C}$$
  where the product is over all maps from $X$ to compact Hausdorff spaces $C$. This works intuitively but fails for the technical reason that the collection of all such maps is a proper class rather than a set. There are several ways to modify this idea to make it work; for example, one can restrict the compact Hausdorff spaces $C$ to have underlying set $P(P(X))$ (the power set of the power set of $X$), which is sufficiently large that it has cardinality at least equal to that of every compact Hausdorff set to which $X$ can be mapped with dense image.

Forget the caveat about sets and proper classes, I'm just trying to understand the idea.  My question is, what does ${\displaystyle \prod C}$ mean?  I don't understand "the product is over all maps from $X$ to compact Hausdorff spaces $C$".  What exactly are we taking a product of?  
Are we taking a Cartesian product of compact Hausdorff spaces, or are we taking some kind of product of maps, or what?

REPLY [3 votes]: Let $S$ be the set* of all continuous maps $f:X\to C$ where $C$ can be any compact Hausdorff space.  Then the product in question is the product $$\prod_{f\in S}\operatorname{codomain}(f).$$  That is, the index set of the product is $S$, and the factor corresponding to each map $f:X\to C$ in $S$ is the space $C$.  This is just an ordinary product of topological spaces.
Denoting this product by $P$, there is a canonical map $F:X\to P$.  Namely, for each $f\in S$, the $f$-coordinate of $F$ is just $f$.  That is, $F(x)(f)=f(x)$.  The Stone-Cech compactification of $X$ is then (modulo set-theoretic issues) the closure of the image of this map $F$.
*OK, it's actually only a class, but that's not important here.