TITLE: What distinguished the Möbius strip from the cylinder as fibre bundles?
QUESTION [10 upvotes]: I'm a physicist trying to understand fibre bundles, and I think I'm pretty happy with the wikipedia definition "a space that is locally a product space, but globally may have a different topological structure". I think I also have a grasp, in the general and tangent cases, on the different objects in the fibre bundle: $(E, \pi, M, F, G)$ taken singularly and abstractly. However, I'm having trouble seeking what tells apart two fibre bundles $E$, the Möbius strip and the cylinder. Both have base $M=S^1$ and fibre $F=$ (a segment), so what's different in the two of them? Is it the projection $\pi$, the structure group $G$ or maybe trivially just the total space $E$?

REPLY [6 votes]: The cylinder, as a fiber bundle, has a section which is never zero.
On the moebius band, such a section does not exist: if you parametrize the segment $F$, which is the fiber, with $(-1,1)$, then if a never-vanishing section starts positive, after one turn it becomes negative.
In terms of fiber bundles a section is a continuous map from the base to the fiber, that is to say a map $$s:M\to E$$ such that $\pi(s(x))=x$ for evey $x\in M$ (so $s(x)$ is in the fiber of $x$).

EDIT following a comment:
To be precise, one should make a difference between fiber bundles and vector bundles: In the case of fiber bundles, the fiber has no vectorial sturcture, so it is not defined who is the zero of the fiber, so the zero section is not defined. So, to be coherent with terminology of fiber bundles, one should say that the Moebius strip, as a fiber bundle, has not two sections that are everywhere different from each other, while the cylinder has plenty of that.