TITLE: When is Ad(pi) an irreducible representation ?
QUESTION [7 upvotes]: For a finite group $G$ with a representation $\pi:G\to GL_n(\mathbb C)$ one can define the adjoint representation $Ad$ as the non-trivial summand in $End(\pi)$, i.e.
$End(\pi)=\pi\otimes \pi^{\vee}=1\oplus Ad(\pi)$.  
For example, if $\pi$ is self-dual then $\pi\otimes \pi=Sym^2(\pi)\oplus \bigwedge^2(\pi)$, and for $n>2$ it is possible to show that $Ad(\pi)$ is reducible. 
Are there any known examples when $Ad(\pi)$ is irreducible ?

REPLY [5 votes]: Derek Holt has given a bunch of examples for $n>2$. In the case $n=2$, $Ad \pi$ is irreducible
if and only if it does not contain a character $\chi$ (since it has dimension 3), that is if and only if the two condition holds:
$Hom_G(\pi,\pi)$ has dimension $1$, and $Hom_G(\pi,\pi(\chi))$ has dimension $0$ for every non-trivial character $\chi$. Now the first condition is automatic by Schur's lemma (since $\pi$ is assumed irreducible) and the second one is equivalent to $ \pi \not \simeq \pi(\chi)$ for 
every non-trivial character $\chi$. Now if for instance you take a group which has no non-trivial character $\chi$ (that is a group whose abelianization is trivial, a.k.a a prefect group), and an irreducible representation $\pi$ of dimension $2$ of that group, you get an example as you asked for, that is such that $Ad \pi$ is irreducible. For example if consider a subgroup $G$ of $Gl_2(\mathbb C)$ is isomorphic to $A_5$, and $\pi$ the canonical representation, then you get an example. (Edit: actually, "2.A_5", see the comments below)