TITLE: Compact objects in undercategories and filtered colimits
QUESTION [7 upvotes]: Let $\mathcal{C}$ be a compactly generated presentable $(\infty, 1)$-category. Consider the functor 
$$ \Phi: \mathcal{C} \to \mathrm{Cat}_\infty, \quad x \mapsto (\mathcal{C}_{x/})^\omega,$$
that sends an object $x \in \mathcal{C}$ to the $(\infty, 1)$-category of compact objects in the undercategory $(\mathcal{C}_{x/})$. 
I am interested in when this functor commutes with filtered colimits. 
I believe that if $\{x_i\}_{i \in I}$ is a filtered diagram of objects in $\mathcal{C}$, then the induced functor
$$\varinjlim 
\Phi(x_i) \to \Phi( \varinjlim x_i),$$
is  (for formal reasons) always fully faithful, and that the image contains those objects of $\mathcal{C}_{\varinjlim x_i/}$ which are both compact and $n$-cotruncated. However, I do not know if this functor is essentially surjective in general: the problem is that the filtered colimit of idempotent complete categories need not be idempotent complete (I think?); the "image" of an idempotent is not a finite colimit. 
For ordinary categories, the above displayed functor is an equivalence of categories (for instance, if $\mathcal{C}$ consists of commutative rings, and compact objects correspond to finitely presented algebras); I'm wondering if something goes wrong with $(\infty, 1)$-categories?

REPLY [5 votes]: In fact, a filtered colimit of idempotent complete $\infty$-categories is idempotent complete. See Lemma 7.3.5.16 of Higher Algebra (in the 2014 edition). This gives an affirmative answer to the above question.