TITLE: Is there a linearly Lindelöf non-Lindelöf $P$-space?
QUESTION [9 upvotes]: A completely regular topological space $(X,\tau)$ is a $P$-space, if every $G_\delta$-subset of $X$ is open (i.e $\tau$ is closed under countable intersections). 
A topological space $X$ is linearly Lindelöf if every open cover of $X$ which is linearly ordered by the subset relation has a countable subcover.
Is there a linearly Lindelöf non-Lindelöf $P$-space?

REPLY [6 votes]: It was shown by A.K. Misra in "A topological view of $P$-spaces" that any regular $\aleph_1$-Lindelöf $P$-space is normal (see Corollary 4.6). Also, it is not hard to see that any linearly Lindelöf space must be $\aleph_1$-Lindelöf.
Finding a normal linearly Lindelöf non-Lindelöf space is a very well known open problem in general topology. So now I´m pretty sure that your question is also open.
Edit: As pointed out by Robson (see comment below), the notion of $\aleph_1$-Lindelöf used by Misra in his paper doesn't correspond to modern terminology. So I don´t know if a regular linearly Lindelöf $P$-space must be normal. However the following is question 486 in "Open problems in topology II":

(Arhangel´ski) Is the product of two linearly Lindelöf $P$-spaces Lindelöf?

So I still think that the OP´s question is open, since product of two Lindelöf $P$-spaces is Lindelöf (so it is the same question after all).