TITLE: A Question on 1, 2 ,3 Conjecture
QUESTION [25 upvotes]: The 1, 2, 3 conjecture is well-known:
If $G$ is a simple graph which is not $K_2$ then one can assign a number among $1, 2, 3$ to every edge such that if we label each vertex with the sum of the numbers of edges incident with it then we obtain a proper vertex coloring.
Question: Is the following weaker statement true?
For any simple graph $G$ there are three natural numbers $p_G, q_G, r_G$ such that if :
(a) We label any edge of $G$ with a number among $p_G, q_G, r_G$.
(b) We label any vertex of $G$ with the sum of numbers of the incident edges.
Then the vertex labels form a proper vertex coloring of the $G$.
Remark: In other words the question is about the truth of the $1, 2, 3$ conjecture when we replace global numbers $1, 2, 3$ with numbers localized to each given $G$.

REPLY [19 votes]: If you choose $p_G$, $q_G$ and $r_G$, such that $p_G>\Delta~q_G>\Delta^2~r_G>0$, (with $\Delta=\Delta(G)$), then your question is equivalent to "neighbor distinguishing colorings by multisets".
As far as I know, the best known bound for this problem is proved here:
L. Addario-Berry, R. E. L. Aldred, K. Dalal, and B. A. Reed. Vertex colouring
edge partitions. J. Combin. Theory Ser. B, 94(2):237–244, 2005.
They prove that four different edge labels are sufficient, three should be open.