TITLE: Are ramified covering of negatively curved manifolds negatively curved?
QUESTION [5 upvotes]: Gromov and Thurston proved in "Pinching constants for hyperbolic manifolds" that any finite ramified covering of a compact hyperbolic manifold, along a codimension $2$ totally geodesic submanifold, can be endowed with a riemannian metric of negative sectional curvature. Pansu mentions in a survey (4/TSG_1985-1986_4_101_0/TSG_1985-1986_4_101_0.pdf">http://archive.numdam.org/ARCHIVE/TSG/TSG_1985-1986_4/TSG_1985-1986_4_101_0/TSG_1985-1986_4_101_0.pdf) that he doesn't know how to make Gromov and Thurston's calculation in the general case. Is it possible to generalize ? 
Namely let $M$ be a compact manifold endowed with a riemannian metric of negative sectional curvature. Suppose $X \longrightarrow M$ is a ramified covering of finite degree, along a compact submanifold of codimension $2$. Can $X$ be endowed with a riemannian metric of negative sectional curvature ? Can a counterexample be found when the locus of ramification is not totally geodesic ? Can one hope a pinching of the curvature like Gromov and Thurston ? Is the covering, in any reasonable sense, "more negatively" than the base ?

REPLY [5 votes]: In the case of 3-dimensional negatively curved manifolds, this result was proved by Yong Hou (at least when the submanifold is totally geodesic; as Misha says, this is the most natural interpretation of your question). The statement is a generalization of Theorem 3.2 of his paper, 
which applies as stated only to cyclic covers branched over a null-homologous geodesic; however it's clear that the proof generalizes to arbitrary branched covers since it is purely local. The idea of his proof is to show that in a tubular neighborhood of the metric, one may make a deformation in which the core geodesic has a neighborhood with constant negative sectional curvature (this sort of argument goes back to Gao). Then one may perform the change in curvature exactly as in the case of Gromov-Thurston.  
So one could try to emulate Hou's proof in higher dimensions, but I don't know if this has been carried out.