TITLE: Random walk by simplex vertices
QUESTION [5 upvotes]: I apologize if this question is well-known, but I was unable to find it mentioned anywhere.
There exists a bug which moves around in $r$-space. The bug begins at the origin of this $r$-space. If the bug is at the center of a regular $r$-simplex (all of which are oriented the exact same direction) with radial length of $1$, then the bug moves to one vertex of the simplex chosen at random with equal probabilities for each vertex. Call each instance of the bug moving, a step.
My question is: What is the probability, as a function of $r$, that there exists a number $n>0$ such that just after the $n$th step, the bug is at the origin?
An equivalent question is:
Given an infinite sequence of digits, with any given digit in the sequence being randomly chosen with equal probabilities inclusively between $0$ and $b$, what is the probability, as a function of $b+1$, that there exists a point in the sequence such that there are an equal number of occurrences of all $b$ digits out of the digits up to that point?
Some work I have done has provided me with a solution that is not in closed form:
$$-\sum_{k\in A}\left(\prod_{i=1}^{k_{length}}\frac{-(r k_i)!}{(r^{k_i} (k_i!))^r}\right)$$
where $A$ is the set of all finite sequences of distinct integers and $k_{length}$ is the length of the sequence $k$.
Unfortunately, I cannot remember how I obtained this result; if I recreate it, I will edit this question. I also have a lower bound of $0.7$ for $r=2$ as calculated by Mathematica.
EDIT:
I'm starting to doubt my expression above as the answer.

REPLY [4 votes]: Thanks to Ben Barber's answer, one can represent your question as follows.
Let $u_i$ be an i.i.d. sequence of  unit vectors of length $r+1$
with exactly one entry nonzero, and set $S_n=\sum_{i=1}^n u_i$. 
Return to the origin at time $n$ 
corresponds to the event $A_n=\{S_n(j)=n/(r+1), j=1,\ldots,r\}$.
Once one hits the main diagonal, the process restarts, so 
a transience/recurrence criterion is whether $\sum_n P(A_n)<\infty$.
Now, because $S_n(1)$ is binomial(n,1/(r+1)), for $n$ an integer multiple
of $r+1$,
$$P(S_n(1)=n/(r+1))\sim c_1/\sqrt{n}$$
and, for $j=2,\ldots,r$, 
$$P(S_n(j)= n/(r+1)|S_n(j')=n/(r+1), j'=1,\ldots,j-1)\sim c_j/\sqrt{n}.$$ 
Therefore,
$$P(A_n)\sim c/n^{r/2}$$
which implies recurrence for $r=2$ and transience for $r\geq 3$.
The probability in the OP is thus $1$ for $r=2$. As to the probability
for $r>2$, an exact computation seems out of reach, but the asymptotics as
$r\to\infty$ is dominated by the first cycle returning to $0$, i.e.
by $\prod_{j=2}^{r}(1-j/(r+1))\sim c e^{-r}$.