TITLE: Can every finite graph be represented by an arithmetic sequence of natural numbers?
QUESTION [5 upvotes]: (This is a follow-up to my previous questions Natural models of graphs?.)
Erdös in The Representation of a Graph by Set Intersections (1966) states:

Theorem. Let $G$ be an arbitrary
  graph. Then there is a set $S$ and a
  family of subsets $S_1, S_2, ...$ of
  $S$ which can be put into one-to-one
  correspondence with the vertices of
  $G$ in such a way that $x_i$ and $x_j$ are joined by an
  edge of $G$ iff $i \neq j$
  and $S_i \cap S_j \neq \emptyset$.

If we identify $S$ with a set of prime numbers and each $S_i$ with the product of its members we get the following:

Corollary. Let $G$ be an arbitrary finite
  graph. Then there is a sequence of natural numbers $(n_1, n_2, ..., n_k)$ 
  which can be put into one-to-one
  correspondence with the vertices of
  $G$ in such a way that  $x_i$ and $x_j$ are joined by an edge iff $i \neq j$ and GCD$(n_i, n_j) > 1$.

We can choose the prime numbers (the elements of $S$, from which the $n_i$ are built) arbitrarily, and so the question arises, whether they can always be choosen in such a way, that the set $(n_1, n_2, ..., n_k)$ is an arithmetic sequence. 
Of course every complete graph on $k$ nodes can be represented by an arithmetic sequence: just take some consecutive sequence of even numbers. Green-Tao's Theorem guarantees that also every empty graph on $k$ nodes can be represented by an arithmetic sequence $(p_1, p_2, ..., p_k)$ of primes.

Question: Can every graph on $k$ nodes be represented by an arithmetic sequence
  of natural numbers such that  $n_i$ and $n_j$ are joined by an edge iff $n_i \neq n_j$ and GCD$(n_i, n_j) > 1$

This would be one kind of natural model of a graph, that I was looking for, originally.
Maybe some references?
Added: Due to Kevin's concise answer and Thomas' comment, I'd like to add the following question:

Question: If not every graph on $k$ nodes can be represented by an arithmetic sequence
  of natural numbers such that  $n_i$ and $n_j$ are joined by an edge iff $n_i \neq n_j$ and GCD$(n_i, n_j) > 1$: Are there interesting classes of graphs with this property?

REPLY [11 votes]: OK so take the unique tree on 3 vertices. Claim: you can't encode this with an arithmetic progression (AP). For if the AP is $a,a+d,a+2d$ then (because we have two edges) either vertices 1 and 2 are joined, or vertices 2 and 3 are joined (or both). Hence there is some $p>1$ such that either $p$ divides both $a$ and $a+d$, or $p$ divides both $a+d$ and $a+2d$. In either case, $p$ then divides $d$, so it divides $a$, so it divides everything, so the graph is complete.